• Per =?UTF-8?B?Tm9yZGzDtnc=?= (5/5) Jan 06 2020 Is there a reason why
• drug (5/8) Jan 06 2020 That's because you try to assign int, not long. This works:
• Steven Schveighoffer (7/17) Jan 06 2020 I think his question is, why shouldn't this work? e.g., this works:
• drug (2/5) Jan 06 2020 Ah, indeed. Sorry for noise.

Per =?UTF-8?B?Tm9yZGzDtnc=?= <per.nordlow gmail.com> writes:

Is there a reason why

     alias A = Algebraic!(long, string);
     A x;
     x = 42;

doesn't implicitly convert `42` to `long` and stores it in `x`?

drug <drug2004 bk.ru> writes:

06.01.2020 20:08, Per Nordlöw пишет:
 alias A = Algebraic!(long, string);
      A x;
      x = 42;

That's because you try to assign int, not long. This works:

alias A = Algebraic!(long, string);
A x;
x = 42L;

Steven Schveighoffer <schveiguy gmail.com> writes:

On 1/6/20 2:33 PM, drug wrote:
 06.01.2020 20:08, Per Nordlöw пишет:
 alias A = Algebraic!(long, string);
      A x;
      x = 42;

 
 That's because you try to assign int, not long. This works:
 
 alias A = Algebraic!(long, string);
 A x;
 x = 42L;

I think his question is, why shouldn't this work? e.g., this works:

long x;
x = 42;

FWIW, 3rd-party algebraic types (e.g. TaggedAlgebraic) will do a 
conversion for this.

-Steve

drug <drug2004 bk.ru> writes:

06.01.2020 22:48, Steven Schveighoffer пишет:
 
 I think his question is, why shouldn't this work? e.g., this works:
 

Ah, indeed. Sorry for noise.