• closescreen (11/11) Jul 15 2017 Let i have code:
• closescreen (8/8) Jul 15 2017 I found this solution:
• =?UTF-8?Q?Ali_=c3=87ehreli?= (16/27) Jul 15 2017 I would probably write a function:
• closescreen (1/1) Jul 16 2017 Thanks for reply, Ali.

closescreen <close.screen gmail.com> writes:

Let i have code:

Clock.currTime.to!DateTime.Interval!DateTime( 24.hours 
).fwdRange( h=>h+1.hours ).writeln;

Now if i want to set the minute=0 and second=0 without breaking 
chain, what i should do?


I think about somewhat like:

with( Clock.currTime.to!DateTime){
  minute=0;
  second=0
}.Interval!DateTime( 24.hours ).fwdRange( h=>h+1.hours ).writeln;

But it is wrong, because 'with' not return me anything.

closescreen <close.screen gmail.com> writes:

I found this solution:

Clock.currTime.to!DateTime.pipe!( dt=>(dt.minute=0,dt.second=0, 
dt) ).Interval!DateTime( 24.hours ).fwdRange( h=>h+1.hours 
).writeln;

Or:

Clock.currTime.to!DateTime.pipe!( "a.minute=0, a.second=0, a" 
).Interval!DateTime( 24.hours ).fwdRange( h=>h+1.hours ).writeln;



Is this code looks good, idiomatic?

=?UTF-8?Q?Ali_=c3=87ehreli?= <acehreli yahoo.com> writes:

On 07/15/2017 12:53 PM, closescreen wrote:
 Let i have code:

 Clock.currTime.to!DateTime.Interval!DateTime( 24.hours ).fwdRange(
 h=>h+1.hours ).writeln;

 Now if i want to set the minute=0 and second=0 without breaking chain,
 what i should do?


 I think about somewhat like:

 with( Clock.currTime.to!DateTime){
  minute=0;
  second=0
 }.Interval!DateTime( 24.hours ).fwdRange( h=>h+1.hours ).writeln;

 But it is wrong, because 'with' not return me anything.

I would probably write a function:

import std.datetime;
import std.stdio;
import std.range;
import std.conv;

DateTime hourPrecision(DateTime dt) {
     dt.minute = 0;
     dt.second = 0;
     return dt;
}

void main() {
     Clock.currTime.to!DateTime.hourPrecision.Interval!DateTime( 
24.hours ).fwdRange( h=>h+1.hours ).writeln;
}

Ali

closescreen <close.screen gmail.com> writes:

Thanks for reply, Ali.