• Serg Kovrov (8/17) Aug 15 2006 Why this one not:
• Pragma (7/31) Aug 15 2006 The problem here is that a template() declaration is a scope that

Serg Kovrov <kovrov no.spam> writes:

Hello everybody,

If this mixin example works:

 template Foo(T)
 {
     T x = 5;
 }

Why this one not:

 template Foo(T)
 {
     T x;
     x = 5; // <- error: no identifier for declarator x
 }

On page describing mixins I never saw an example with assignment inside 
mixin body, is it limitation of language or bug?

Thanks.

--
serg.

Pragma <ericanderton yahoo.removeme.com> writes:

Serg Kovrov wrote:
 Hello everybody,
 
 If this mixin example works:
 
 template Foo(T)
 {
     T x = 5;
 }

 
 Why this one not:
 
 template Foo(T)
 {
     T x;
     x = 5; // <- error: no identifier for declarator x
 }

 
 On page describing mixins I never saw an example with assignment inside 
 mixin body, is it limitation of language or bug?
 
 Thanks.
 
 -- 
 serg.

The problem here is that a template() declaration is a scope that 
contains other declarations - it is not a scope that contains code. 
This is why it complains about their being 'no identifier for 
declarator', as it was expecting a type before the 'x'.

-- 
- EricAnderton at yahoo