• jicman (15/15) Mar 31 2006 I am trying to get rid of the first item of an array, so I am trying to ...
• Deewiant (7/30) Mar 31 2006 For one thing, it does it in-place, so you can just "a.reverse;" instead...
• jicman (4/34) Mar 31 2006 Yeah... This one would be much faster... :-) I had forgotten about thi...
• BCS (9/11) Mar 31 2006 watch out for this though

jicman <jicman_member pathlink.com> writes:

I am trying to get rid of the first item of an array, so I am trying to figure
it out what is the best way.  Right I I thought of this,

char[][] a;
a[0] = "a";
a[1] = "b";
a[2] = "c";
a[3] = "d";

so if I want to get rid of the first one, I do

a = a.reverse
a.length = a.length - 1;
a = a.reverse;

But now I am thinking that what if the array is huge.  So, what does
array.reverse really does?

thanks,

josé

Deewiant <deewiant.doesnotlike.spam gmail.com> writes:

jicman wrote:
 I am trying to get rid of the first item of an array, so I am trying to figure
 it out what is the best way.  Right I I thought of this,
 
 char[][] a;
 a[0] = "a";
 a[1] = "b";
 a[2] = "c";
 a[3] = "d";
 
 so if I want to get rid of the first one, I do
 
 a = a.reverse
 a.length = a.length - 1;
 a = a.reverse;
 
 But now I am thinking that what if the array is huge.  So, what does
 array.reverse really does?
 
 thanks,
 
 josé
 
 

For one thing, it does it in-place, so you can just "a.reverse;" instead of "a =
a.reverse;".

For another, to get rid of the first array element, I suggest "a = a[1..$]",
which I would expect to be faster.

As to your question, I don't really know. Have a look at
dmd\src\phobos\internal\adi.d, which has the code.

jicman <jicman_member pathlink.com> writes:

Deewiant says...
jicman wrote:
 I am trying to get rid of the first item of an array, so I am trying to figure
 it out what is the best way.  Right I I thought of this,
 
 char[][] a;
 a[0] = "a";
 a[1] = "b";
 a[2] = "c";
 a[3] = "d";
 
 so if I want to get rid of the first one, I do
 
 a = a.reverse
 a.length = a.length - 1;
 a = a.reverse;
 
 But now I am thinking that what if the array is huge.  So, what does
 array.reverse really does?
 
 thanks,
 
 josé
 
 

For one thing, it does it in-place, so you can just "a.reverse;" instead of "a =
a.reverse;".

For another, to get rid of the first array element, I suggest "a = a[1..$]",
which I would expect to be faster.

Yeah...  This one would be much faster... :-)  I had forgotten about this.
Gosh, and I even used it a few months back... Read The Great Manual. :-)

Thanks.

As to your question, I don't really know. Have a look at
dmd\src\phobos\internal\adi.d, which has the code.

BCS <BCS_member pathlink.com> writes:

In article <e0jrkd$2ou$1 digitaldaemon.com>, Deewiant says...

For another, to get rid of the first array element, I suggest "a = a[1..$]",
which I would expect to be faster.


watch out for this though



int[] a = [1, 2, ..stuff...]
int[] b = a;

b = b[1..$];

assert(b[0] == a[0]);  //fails because only where b points to is changed.



somthing like this is needed to change the contents



foreach(int i, int j; a[1..$])
b[i] = j;