digitalmars.D - is(T t == U!n, U, int n)
- =?UTF-8?B?THXDrXM=?= Marques (35/35) Jun 13 2018 If this works:
- Simen =?UTF-8?B?S2rDpnLDpXM=?= (23/27) Jun 13 2018 U needs to be alias U, since S is not a type, but a template.
- =?UTF-8?B?THXDrXM=?= Marques (9/11) Jun 13 2018 You're right. What happened is that I went to check the syntax in
If this works: template X(T) { static if(is(T t == S!n, int n)) { static if(n == 0) alias X = AliasSeq!(); else alias X = S!0; } else { static assert(0); } } class S(int n) { } pragma(msg, X!(S!3)); // S!0 pragma(msg, X!(S!0)); // () ...why can't I generalize it to match U!n, for some U, int n? template X(T) { static if(is(T t == U!n, U, int n)) { static if(n == 0) alias X = AliasSeq!(); else alias X = U!0; } else { static assert(0); } } class S(int n) { } pragma(msg, X!(S!3)); // static assert: 0
Jun 13 2018
On Wednesday, 13 June 2018 at 09:41:45 UTC, Luís Marques wrote:...why can't I generalize it to match U!n, for some U, int n? template X(T) { static if(is(T t == U!n, U, int n))U needs to be alias U, since S is not a type, but a template. This works: template X(T) { static if(is(T t == U!n, alias U, int n)) { static if(n == 0) alias X = AliasSeq!(); else alias X = U!0; } else { static assert(0); } } class S(int n) { } pragma(msg, X!(S!3)); Also, you might want to consider the Learn forum for these kinds of questions in the future. :) -- Simen
Jun 13 2018
On Wednesday, 13 June 2018 at 10:34:48 UTC, Simen Kjærås wrote:Also, you might want to consider the Learn forum for these kinds of questions in the future. :)You're right. What happened is that I went to check the syntax in the "D Templates: A Tutorial" PDF, and it has some material on how some possible uses of is expressions used to not be accepted by the frontend, so I though this might be a similar case: perhaps a bug or an unsupported scenario. A bit arrogant on my part, but I do stumble into bugs from time to time, so it was plausible :-). And if it was a bug/limitation then arguably this was the better forum.
Jun 13 2018