digitalmars.D - how to propagate computed type during CTFE?
- Timothee Cour (29/29) Feb 22 2018 in example below, how do I propagate RET (or even `typeof(a)`) to the
- rikki cattermole (2/37) Feb 22 2018 Yeah I've tried, I can't think of any way to do this.
- Simen =?UTF-8?B?S2rDpnLDpXM=?= (5/9) Feb 22 2018 No can do. Consider what would happen if you added put(1); inside
- Stefan Koch (5/36) Feb 23 2018 Yes there is a language change required for this.
in example below, how do I propagate RET (or even `typeof(a)`) to the result value of `inferType`? does this need a language change to allow this? ``` template inference(alias emitter) { auto inference(){ auto inferType(){ emitter!((a){ enum RET=typeof(a).stringof; // type is known here, how to propagate? pragma(msg, RET); // string }) (); return "unknown"; } // how to get RET? (or even typeof(a) ) enum temp=inferType; pragma(msg, temp); } } void main(){ static void fun(alias put)(){ put("hello"); } inference!fun; } ``` use case: allow type inference in `emit` https://github.com/timotheecour/dtools/blob/master/dtools/util/emit.d (see forum discussion here: https://forum.dlang.org/post/mailman.538.1458560190.26339.digitalmars-d puremagic.com)
Feb 22 2018
On 23/02/2018 1:54 PM, Timothee Cour wrote:in example below, how do I propagate RET (or even `typeof(a)`) to the result value of `inferType`? does this need a language change to allow this? ``` template inference(alias emitter) { auto inference(){ auto inferType(){ emitter!((a){ enum RET=typeof(a).stringof; // type is known here, how to propagate? pragma(msg, RET); // string }) (); return "unknown"; } // how to get RET? (or even typeof(a) ) enum temp=inferType; pragma(msg, temp); } } void main(){ static void fun(alias put)(){ put("hello"); } inference!fun; } ``` use case: allow type inference in `emit` https://github.com/timotheecour/dtools/blob/master/dtools/util/emit.d (see forum discussion here: https://forum.dlang.org/post/mailman.538.1458560190.26339.digitalma s-d puremagic.com)>Yeah I've tried, I can't think of any way to do this.
Feb 22 2018
On Friday, 23 February 2018 at 00:54:34 UTC, Timothee Cour wrote:in example below, how do I propagate RET (or even `typeof(a)`) to the result value of `inferType`? does this need a language change to allow this?No can do. Consider what would happen if you added put(1); inside fun - what should temp become? -- Simen
Feb 22 2018
On Friday, 23 February 2018 at 00:54:34 UTC, Timothee Cour wrote:in example below, how do I propagate RET (or even `typeof(a)`) to the result value of `inferType`? does this need a language change to allow this? ``` template inference(alias emitter) { auto inference(){ auto inferType(){ emitter!((a){ enum RET=typeof(a).stringof; // type is known here, how to propagate? pragma(msg, RET); // string }) (); return "unknown"; } // how to get RET? (or even typeof(a) ) enum temp=inferType; pragma(msg, temp); } } void main(){ static void fun(alias put)(){ put("hello"); } inference!fun; } ``` use case: allow type inference in `emit` https://github.com/timotheecour/dtools/blob/master/dtools/util/emit.d (see forum discussion here: https://forum.dlang.org/post/mailman.538.1458560190.26339.digitalmars-d puremagic.com)Yes there is a language change required for this. Currently types are untouchable entities. I plan to introduce a mechanism which'll give you first-class types inside a bounded semantic construct.
Feb 23 2018