digitalmars.D.bugs - [Issue 6621] New: Superimposition amount for std.range.chunks
- d-bugmail puremagic.com (30/30) Sep 08 2011 http://d.puremagic.com/issues/show_bug.cgi?id=6621
- d-bugmail puremagic.com (30/30) Apr 27 2013 http://d.puremagic.com/issues/show_bug.cgi?id=6621
http://d.puremagic.com/issues/show_bug.cgi?id=6621
Summary: Superimposition amount for std.range.chunks
Product: D
Version: D2
Platform: All
OS/Version: All
Status: NEW
Severity: enhancement
Priority: P2
Component: Phobos
AssignedTo: nobody puremagic.com
ReportedBy: bearophile_hugs eml.cc
std.range.chunks is quite useful. For it a rather useful third optional
argument (that defaults to 0) is how many items are repeated from the precedent
chunk:
auto data = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
chunks(data, 3, 0) ==> (default, as now)
[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10]]
chunks(data, 3, 1) ==>
[[1, 2, 3], [3, 4, 5], [5, 6, 7], [7, 8, 9], [9, 10]]
chunks(data, 3, 2) ==>
[[1, 2, 3], [2, 3, 4], [3, 4, 5], [4, 5, 6], [5, 6, 7], [6, 7, 8], [7, 8, 9],
[8, 9, 10]]
In Python I use now and then a lazy generator with such extra argument.
The third argument can't be higher than the second (if they are equal it's like
cycle on a slice).
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Sep 08 2011
http://d.puremagic.com/issues/show_bug.cgi?id=6621
A simple use case, count the number of local maxima in an array (a number is a
local maxima if it is greater than the number before and after it):
size_t countMaxima(T)(in T[] xs) pure nothrow
if (__traits(compiles, T.init > T.init)) {
if (xs.length < 2)
return xs.length;
typeof(return) count = 0;
foreach (immutable i; 1 .. xs.length - 1)
count += xs[i] > xs[i - 1] && xs[i] > xs[i + 1];
return count + (xs[0] > xs[1]) + (xs[$ - 1] > xs[$ - 2]);
}
Using chunks() with the second argument the code avoids some bug-prone indexes
(this is component programming):
size_t countMaxima(T)(in T[] xs) pure nothrow
if (__traits(compiles, T.init > T.init)) {
if (xs.length < 2)
return xs.length;
auto count = xs
.chunks(3, 2)
.filter!(c => c[1] > c[0] && c[1] > c[2])
.walkLength;
return count + (xs[0] > xs[1]) + (xs[$ - 1] > xs[$ - 2]);
}
Another use case:
http://forum.dlang.org/thread/zdhfpftodxnvbpwvklcv forum.dlang.org
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Apr 27 2013








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