digitalmars.D.bugs - [Issue 6126] New: std.parallelism does not re-throw exception
- d-bugmail puremagic.com (37/37) Jun 08 2011 http://d.puremagic.com/issues/show_bug.cgi?id=6126
- d-bugmail puremagic.com (31/31) Jun 08 2011 http://d.puremagic.com/issues/show_bug.cgi?id=6126
http://d.puremagic.com/issues/show_bug.cgi?id=6126
Summary: std.parallelism does not re-throw exception
Product: D
Version: D2
Platform: Other
OS/Version: Mac OS X
Status: NEW
Severity: normal
Priority: P2
Component: Phobos
AssignedTo: nobody puremagic.com
ReportedBy: robert octarineparrot.com
21:17:51 BST ---
The following code:
----
import std.exception;
import std.parallelism;
void foo(int task)
{
enforce(task != 4);
}
void main()
{
int[] tasks = [1, 2, 3];
taskPool.put(task!foo(4));
foreach (task; taskPool.parallel(tasks))
{
foo(task);
}
}
----
Does not re-throw the exception when the task uses .put() then .parallel() is
used to run the tasks. Changing the enforcement to == causes three exceptions
to be thrown as expected.
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Jun 08 2011
http://d.puremagic.com/issues/show_bug.cgi?id=6126
David Simcha <dsimcha yahoo.com> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|NEW |RESOLVED
Resolution| |INVALID
Exceptions thrown from within tasks are re-thrown when you call done(),
workForce(), yieldForce(), or spinForce() on the Task object. You created an
anonymous task and never called any of these functions. The following slightly
modified code does re-throw the exception.
import std.exception;
import std.parallelism;
void foo(int task)
{
enforce(task != 4);
}
void main()
{
int[] tasks = [1, 2, 3];
auto t = task!foo(4);
taskPool.put(t);
foreach (task; taskPool.parallel(tasks))
{
foo(task);
}
t.yieldForce();
}
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