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digitalmars.D.bugs - [Issue 3395] New: Ambiguous array operations

reply d-bugmail puremagic.com writes:
http://d.puremagic.com/issues/show_bug.cgi?id=3395

           Summary: Ambiguous array operations
           Product: D
           Version: 2.032
          Platform: All
               URL: http://www.digitalmars.com/d/2.0/arrays.html
        OS/Version: All
            Status: NEW
          Keywords: spec
          Severity: enhancement
          Priority: P2
         Component: DMD
        AssignedTo: nobody puremagic.com
        ReportedBy: dfj1esp02 sneakemail.com



01:15:48 PDT ---
These expressions are ambiguous:
---
a[].max(n);
a[1..4].max(n);
---
Does it mean calling the function on the slice or on each item in the slice?

Possible solution is to change the meaning of empty square brackets from full
slice to only a hint for array operation so that a[].max(n) is an array
operation and a[1..4].max(n) is max(a[1..4],n).
This also gives possibility to extend array operation to whole statement even
if it's not an lvalue:
---
printf("%.4f, ",a[]);
becomes
foreach(v;a)printf("%.4f, ",v);
---
a[].max(n) and max(a[],n) become the same and unambiguous with other use cases.

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next sibling parent d-bugmail puremagic.com writes:
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01:31:43 PDT ---
This also has to do with type safety.
---
a[]=b[];
---
This expression is ambiguous. What was meant? Copy items from b[] slice to a[]
slice or assign b[] slice to each item in a[] slice?
Ambiguity resolution:
---
a[]=b[]; //copy items from b to a
a[]=b; //assign b slice to each item in a slice
a[]=b[0..$]; //ditto
---

And types for the operation must match or an error will be issued.
---
T[] a,b;
a[]=b;
---
Currently this is accepted, but should fail, the right side expression in this
assignment must be of type T (or T[] with array op).

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prev sibling next sibling parent d-bugmail puremagic.com writes:
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Stewart Gordon <smjg iname.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |smjg iname.com





 These expressions are ambiguous:
 ---
 a[].max(n);
 a[1..4].max(n);
 ---
 Does it mean calling the function on the slice or on each item in the slice?


It means calling the function on the slice.  Unless I'm mistaken, there isn't
any D syntax at the moment that means calling the function on each element of
the array.


 Possible solution is to change the meaning of empty square brackets from full
 slice to only a hint for array operation so that a[].max(n) is an array
 operation and a[1..4].max(n) is max(a[1..4],n).


This would get confusing.  You might want to apply a function to the whole
slice [1..4] or to each element of the slice.  This applies whether the
array-property sugar is being used or not.

Perhaps the best solution is to define [] applied to the function identifier
itself to do an elementwise application.

So max(a, n) or a.max(n) would just call max(a, n) once.
And max[](a, n) or a.max[](n) would evaluate to an array of max(a[i], n).
And the same if a is replaced with a[], a[1..4] or some such in each case.

Of course, ambiguities can still occur in functions with multiple array
parameters.  Presumably the language would forbid it in these ambiguous cases,
as it does already with ambiguous overload matching.

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Nov 29 2011
prev sibling next sibling parent d-bugmail puremagic.com writes:
http://d.puremagic.com/issues/show_bug.cgi?id=3395


Don <clugdbug yahoo.com.au> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |clugdbug yahoo.com.au







 These expressions are ambiguous:
 ---
 a[].max(n);
 a[1..4].max(n);
 ---
 Does it mean calling the function on the slice or on each item in the slice?


 
 It means calling the function on the slice.  Unless I'm mistaken, there isn't
 any D syntax at the moment that means calling the function on each element of
 the array.


That's correct.


 Possible solution is to change the meaning of empty square brackets from full
 slice to only a hint for array operation so that a[].max(n) is an array
 operation and a[1..4].max(n) is max(a[1..4],n).





 This would get confusing.  You might want to apply a function to the whole
 slice [1..4] or to each element of the slice.  This applies whether the
 array-property sugar is being used or not.
 
 Perhaps the best solution is to define [] applied to the function identifier
 itself to do an elementwise application.
 
 So max(a, n) or a.max(n) would just call max(a, n) once.
 And max[](a, n) or a.max[](n) would evaluate to an array of max(a[i], n).
 And the same if a is replaced with a[], a[1..4] or some such in each case.


That looks to me as if max is an array of some struct S which defines an
opCall.


 Of course, ambiguities can still occur in functions with multiple array
 parameters.  Presumably the language would forbid it in these ambiguous cases,
 as it does already with ambiguous overload matching.


Consider the case where we want y to be 
[ max(x[2][0..$], max(x[3][0..$], ... ]

double [][20] x;
double [10] y;

Brainstorming a few possibilities:

 y[] = max(x[2..12]);     // (1) looks like scalar assignment
 y[] = max[2..12](x);     // (2)
 y[] = max(x[2..12])[];   // (3)
 y[] = max([] x[2..12]);  // (4)
 y[] = max([] x[2..12])[]; // (5) messy!


(2) does looks like an opCall on array called 'max'. 
(3) looks the most intuitive to me. Not perfect though (I don't think we'd want
y[] = max(x[2..12]); to compile and be a scalar).
(4) is an interesting possibility. Doesn't look great, but it seems to be a
syntax hole. Ambiguous in the one-argument property case: x.max([]) could be:
     max([] x)   or  max(x, []) where the [] is an empty array literal.
I think that's solvable though. Interestingly it's the case where (2) is
cleanest: x.max[];

Can we put the [] _before_ the call? y[] = [] max(x);
y[] = x.[]max;

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prev sibling next sibling parent d-bugmail puremagic.com writes:
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 These expressions are ambiguous:
 ---
 a[].max(n);
 a[1..4].max(n);
 ---
 Does it mean calling the function on the slice or on each item in the slice?


 
 It means calling the function on the slice.  Unless I'm mistaken, there isn't
 any D syntax at the moment that means calling the function on each element of
 the array.


 
 That's correct.
 

 Possible solution is to change the meaning of empty square brackets from full
 slice to only a hint for array operation so that a[].max(n) is an array
 operation and a[1..4].max(n) is max(a[1..4],n).




 

 This would get confusing.  You might want to apply a function to the whole
 slice [1..4] or to each element of the slice.  This applies whether the
 array-property sugar is being used or not.
 
 Perhaps the best solution is to define [] applied to the function identifier
 itself to do an elementwise application.
 
 So max(a, n) or a.max(n) would just call max(a, n) once.
 And max[](a, n) or a.max[](n) would evaluate to an array of max(a[i], n).
 And the same if a is replaced with a[], a[1..4] or some such in each case.


 
 That looks to me as if max is an array of some struct S which defines an
 opCall.
 

 Of course, ambiguities can still occur in functions with multiple array
 parameters.  Presumably the language would forbid it in these ambiguous cases,
 as it does already with ambiguous overload matching.


 
 Consider the case where we want y to be 
 [ max(x[2][0..$], max(x[3][0..$], ... ]
 
 double [][20] x;
 double [10] y;
 
 Brainstorming a few possibilities:
 
  y[] = max(x[2..12]);     // (1) looks like scalar assignment
  y[] = max[2..12](x);     // (2)
  y[] = max(x[2..12])[];   // (3)


That's ambiguous - maybe max is a function that returns an array or other type
with an opSlice().


 Can we put the [] _before_ the call? y[] = [] max(x);
 y[] = x.[]max;


Would [](expr) be the empty array's opCall(expr) or the vectorisation of the
function referenced by expr?  And [].func be a vectorisation of the global
function func or the empty array's .func method?  (Are you envisaging that []
vectorises a whole subexpression or just the function whose name it immediately
precedes?)

FWIW the other week I discovered C++11 variadic templates.  I wonder if we can
draw inspiration from the unpacking syntax here....
http://lanzkron.wordpress.com/2011/11/05/did-you-pack-that-yourself/

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prev sibling parent d-bugmail puremagic.com writes:
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 Consider the case where we want y to be 
 [ max(x[2][0..$]), max(x[3][0..$]), ... ]
 
 double [][20] x;
 double [10] y;
 
 Brainstorming a few possibilities:
 
  y[] = max(x[2..12]);     // (1) looks like scalar assignment
  y[] = max[2..12](x);     // (2)
  y[] = max(x[2..12])[];   // (3)


 
 That's ambiguous - maybe max is a function that returns an array or other type
 with an opSlice().


True. But unlike (1), it's still obvious that it's an element-by-element
assignment. The nett effect is the same as if it were vectorized. Is that an
ambiguity that matters? 


 Can we put the [] _before_ the call? y[] = [] max(x);
 y[] = x.[]max;


 
 Would [](expr) be the empty array's opCall(expr) or the vectorisation of the
 function referenced by expr?  And [].func be a vectorisation of the global
 function func or the empty array's .func method?  (Are you envisaging that []
 vectorises a whole subexpression or just the function whose name it
immediately precedes?)


I was imagining just the function name. At least, I think it would need to have
very high precedence. []a.b is the same as ([]a).b, rather than [](a.b). This,
[].func would be the empty array's .func method, since there is no function
name before the dot. I think then if you wanted to vectorize .func, you'd do it
as: ".[]func". I'm less sure about [](expr) but I think it would just be an
opCall.
But I'm really just brainstorming. It's a wild idea. Haven't given any thought
to if it works with function literals or function pointers. 



 
 FWIW the other week I discovered C++11 variadic templates.  I wonder if we can
 draw inspiration from the unpacking syntax here....
 http://lanzkron.wordpress.com/2011/11/05/did-you-pack-that-yourself/


Yeah, that's interesting, it does look quite similar.

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