• d-bugmail puremagic.com (54/54) Aug 11 2013 http://d.puremagic.com/issues/show_bug.cgi?id=10794

d-bugmail puremagic.com writes:

http://d.puremagic.com/issues/show_bug.cgi?id=10794

           Summary: Unsynchronized access to data of syncronized class
           Product: D
           Version: D2
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: nobody puremagic.com
        ReportedBy: freeslave93 gmail.com



Here is something similar to example from Alexandrescu's book (13.14.1
Temporary Protection == No Escape):

import std.stdio;

int* ptr;

void sneaky(out int bar)
{
    ptr = &bar;
}

synchronized class B
{
    private int bar;
    public void foo()
    {
        sneaky(bar);
    }
    int getBar()
    {
        return bar;
    }
    void setBar(int b)
    {
        bar = b;
    }
}

void main()
{
    auto b = new shared(B);
    b.setBar(5);
    b.foo();
    *ptr = 6;
    writeln(*ptr);
    writeln(b.getBar());
}

I just replaced 'ref' with 'out' and now it compiles fine. Is it suppose to
work this way?

I also wonder why we have to write 'new shared(NameOfClass)' when class is
synchronized, although we can't create not shared instance of synchronized
class. Was it designed to make code more explicit?

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