digitalmars.D.bugs - property as template parameter
- Sark7 (10/10) Jul 06 2004 template foo(int i)
- J C Calvarese (11/22) Jul 24 2004 I know this bug report has been out a while (so you might have already
- Jarrett Billingsley (6/6) Jul 24 2004 you're using a property without knowing what it means? that's a new one...
- J C Calvarese (26/33) Jul 24 2004 Who said I was using it? I'm sometimes careless, but I'm never psychic.
- Jarrett Billingsley (12/12) Jul 24 2004 odd. this is from the D docs, in the "converting C to D" section.
- J C Calvarese (26/40) Jul 25 2004 Okay. I finally got the compiler to recognize offset. So I agree now
template foo(int i) { void foo() { } } void main() { struct S { int bar; } foo!(S.bar.offset)(); // error: identifier 'offset' of 'S.bar.offset' is not defined }
Jul 06 2004
Sark7 wrote:template foo(int i) { void foo() { } } void main() { struct S { int bar; } foo!(S.bar.offset)(); // error: identifier 'offset' of 'S.bar.offset' is not defined }I know this bug report has been out a while (so you might have already solved your problem), but I just looked at this. What is "offset"? I initially thought it was a property of int, but I can't find it on that page of the spec. It's not a keyword. I think that's why the compiler is confused. I'm confused, too. If I'm wrong and there is an offset built into the language, please tell me what it is (and where I can find out about it). It might come in handy. -- Justin (a/k/a jcc7) http://jcc_7.tripod.com/d/
Jul 24 2004
you're using a property without knowing what it means? that's a new one to me ;) offset gives you the offset in bytes of a member variable from the start of a struct. because structs are left in the order they are, and assuming the default alignment is 4 bytes, in struct S { int a,b; }, a.offset=0 and b.offset=4.
Jul 24 2004
Jarrett Billingsley wrote:you're using a property without knowing what it means? that's a new one to me ;) offset gives you the offset in bytes of a member variable from the start of a struct. because structs are left in the order they are, and assuming the default alignment is 4 bytes, in struct S { int a,b; }, a.offset=0 and b.offset=4.Who said I was using it? I'm sometimes careless, but I'm never psychic. ;) I didn't know there was such a thing, and I still can't find a reference to it. Here's what the spec lists as Struct Properties: .sizeof Size in bytes of struct .size Same as .sizeof .alignof Size boundary struct needs to be aligned on As far I can tell there isn't an "offset" property (although "alignof" may be what is desired). import std.stdio; struct S { int bar; } void main() { S myStruct; writef(myStruct.bar); // writef(myStruct.offset); // offset2.d(13): no property 'offset' for type 'S' writef(myStruct.bar.offset); // offset2.d(17): no property 'offset' for type 'int' } -- Justin (a/k/a jcc7) http://jcc_7.tripod.com/d/
Jul 24 2004
odd. this is from the D docs, in the "converting C to D" section. Getting the offset of a struct member. The C Way Naturally, another macro is used: #include <stddef> struct Foo { int x; int y; }; off = offsetof(Foo, y); The D Way An offset is just another property: struct Foo { int x; int y; } off = Foo.y.offset; but the compiler doesn't recognize it?
Jul 24 2004
Jarrett Billingsley wrote:odd. this is from the D docs, in the "converting C to D" section. Getting the offset of a struct member. The C Way Naturally, another macro is used: #include <stddef> struct Foo { int x; int y; }; off = offsetof(Foo, y); The D Way An offset is just another property: struct Foo { int x; int y; } off = Foo.y.offset; but the compiler doesn't recognize it?Okay. I finally got the compiler to recognize offset. So I agree now that the original post does correctly identify a bug. I'm not sure if the bug is a poor error message or if the code is legal, but I'd call it a bug. I'm going to post a new bug complaining about how offset is essentially undocumented (yes, it's on ctod.html, but I think it should be on the struct page, too). import std.stdio; struct S { int bar; } void main() { S myStruct; // writef(myStruct.offset); // offset2.d(13): no property 'offset' for type 'S' // writef(myStruct.bar.offset); // offset2.d(16): no property 'offset' for type 'int' writefln(S.bar.offset); writefln(typeof(myStruct).bar.offset); } -- Justin (a/k/a jcc7) http://jcc_7.tripod.com/d/
Jul 25 2004