• newbee (16/16) Aug 12 2004 Could anyone tell me which part of my program is wrong.
• h3r3tic (5/20) Aug 12 2004 gosh... %f and %e are for floats while sin returns a double... why are

newbee <newbee_member pathlink.com> writes:

Could anyone tell me which part of my program is wrong.
I'm using version 0.98 (download from ftp.digitalmars.com/dmd.zip)
on linux (fedora core 2).

import std.math;

int main( char[][] arg )
{
double d;

d = 0.5;
printf("%f\n", sin(d));
printf("%e\n", sin(d));
return 0;
}

I got the following result. Is it OK?
-698625369815211718378554677465583019603259137860293313598822589260516170206686081027350142193452335800939574198423310222441035662104590869532633447231577762165250828259364817839638699012687998639440540605545556135551400652591406054794302384598256244586708992.000000
-6.986254e+257

Thanks,

h3r3tic <h3r3tic dev.null> writes:

newbee wrote:
 import std.math;
 
 int main( char[][] arg )
 {
 double d;
 
 d = 0.5;
 printf("%f\n", sin(d));
 printf("%e\n", sin(d));
 return 0;
 }
 
 I got the following result. Is it OK?
 -698625369815211718378554677465583019603259137860293313598822589260516170206686081027350142193452335800939574198423310222441035662104590869532633447231577762165250828259364817839638699012687998639440540605545556135551400652591406054794302384598256244586708992.000000
 -6.986254e+257

gosh... %f and %e are for floats while sin returns a double... why are 
you ppl still using printf ? replace that with writefln and get rid of 
%f and \n... just writefln(sin(d)) is fine... then do writefln("%e", 
sin(d)) and again there are no problems...