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digitalmars.D - T.zero and T.one for numeric types

reply "Biotronic" <simen.kjaras gmail.com> writes:
I've been writing a lot of generic code lately that has to deal 
with various kinds of numbers, and have near been driven nuts by 
the fact there is no uniform way to get a zero or one.

Consider:

    void foo(T)(T a) {}

    foo!T(0);

Does this work with all built-in numeric types? Yes.
Does it work with T=BigInt or Complex!float? No.

Now, those are a limited set of possibilities, and one could 
easily enough create a template such that

    foo!BigInt(zero!BigInt);

would work. But why can't I instead, for every numeric type, 
simply write

    foo(BigInt.zero);
    foo(float.one);
    foo(Complex!float.zero);
    foo(Rational!BigInt.one);
    foo(Meters.zero);

?

This would also work for strong typedefs and units of 
measurement, where simply assigning 0 to a variable might not 
work (because it lacks the correct unit).

It's a very simple change, both in the compiler and Phobos, and I 
could have a pull request ready tomorrow.

--
   Simen
Apr 17 2015
next sibling parent reply "Adam D. Ruppe" <destructionator gmail.com> writes:
On Friday, 17 April 2015 at 13:27:19 UTC, Biotronic wrote:
    void foo(T)(T a) {}

    foo!T(0);
Does foo(T(0)); work? It seems like it should void foo(T)(T a) {} import std.bigint; import std.complex; void main() { foo(BigInt(0)); foo(float(0)); foo(int(0)); foo(Complex!float(0)); } as of one of the newish dmds, T(n) works to construct basic types too.
Apr 17 2015
parent "Biotronic" <simen.kjaras gmail.com> writes:
On Friday, 17 April 2015 at 13:33:36 UTC, Adam D. Ruppe wrote:
 On Friday, 17 April 2015 at 13:27:19 UTC, Biotronic wrote:
   void foo(T)(T a) {}

   foo!T(0);
Does foo(T(0)); work? It seems like it should void foo(T)(T a) {} import std.bigint; import std.complex; void main() { foo(BigInt(0)); foo(float(0)); foo(int(0)); foo(Complex!float(0)); } as of one of the newish dmds, T(n) works to construct basic types too.
Man, that actually does work. I guess I've become too used to it not. Sorry about the noise then, and thanks!
Apr 17 2015
prev sibling next sibling parent ketmar <ketmar ketmar.no-ip.org> writes:
On Fri, 17 Apr 2015 13:27:18 +0000, Biotronic wrote:

 would work. But why can't I instead, for every numeric type, simply
 write
=20
     foo(BigInt.zero); foo(float.one); foo(Complex!float.zero);
     foo(Rational!BigInt.one);
     foo(Meters.zero);
Omens.sixsixsix...=
Apr 17 2015
prev sibling parent "w0rp" <devw0rp gmail.com> writes:
On Friday, 17 April 2015 at 13:27:19 UTC, Biotronic wrote:
 I've been writing a lot of generic code lately that has to deal 
 with various kinds of numbers, and have near been driven nuts 
 by the fact there is no uniform way to get a zero or one.

 Consider:

    void foo(T)(T a) {}

    foo!T(0);

 Does this work with all built-in numeric types? Yes.
 Does it work with T=BigInt or Complex!float? No.

 Now, those are a limited set of possibilities, and one could 
 easily enough create a template such that

    foo!BigInt(zero!BigInt);

 would work. But why can't I instead, for every numeric type, 
 simply write

    foo(BigInt.zero);
    foo(float.one);
    foo(Complex!float.zero);
    foo(Rational!BigInt.one);
    foo(Meters.zero);

 ?

 This would also work for strong typedefs and units of 
 measurement, where simply assigning 0 to a variable might not 
 work (because it lacks the correct unit).

 It's a very simple change, both in the compiler and Phobos, and 
 I could have a pull request ready tomorrow.

 --
   Simen
This can be implemented via a library without requiring any changes to the language. It would look like Zero!T or One!T instead. You create a value template for it. When you are writing less generic code, you can commit to zero or one in certain types via the prefixes. 1L, 1, 1.0, 1.0f. There's nothing for short or byte, but you can do short(1), byte(1). You can also write T(1) or T(0) to get a numeric type T with the value 0 or 1. That might be better than a template, I haven't tried it.
Apr 17 2015