• Olivier Pisano (21/21) Nov 12 2010 Hi,
• Steven Schveighoffer (8/27) Nov 12 2010 Expected. If you want an appendable array as an output range, use
• Lars T. Kyllingstad (5/32) Nov 12 2010 Here's a discussion from earlier this year:
• Olivier Pisano (5/9) Nov 12 2010 Thanks to you and Steven.

Olivier Pisano <olivier.pisano laposte.net> writes:

Hi,

I am starting to play with output ranges and have trouble understanding 
how they do work on arrays. Consider the following code :

	import std.array;
	import std.range;
	import std.stdio;

	void main(string[] argv)
	{
	    auto a = [1, 2, 3];
	    a.put(4);

	    writefln("%s", a);
	}

One could expect the call to put() to append 4 to the array so the array 
content would be [1, 2, 3, 4].
Instead of this, I get "[2, 3]" to be printed. So I guess put() is 
translated to

	r.front = e; r.popFront();

as written in std.range.put documentation.

Is it the expected behaviour or is it a bug ?

Cheers,

Olivier.

"Steven Schveighoffer" <schveiguy yahoo.com> writes:

On Fri, 12 Nov 2010 09:22:20 -0500, Olivier Pisano  
<olivier.pisano laposte.net> wrote:

 Hi,

 I am starting to play with output ranges and have trouble understanding  
 how they do work on arrays. Consider the following code :

 	import std.array;
 	import std.range;
 	import std.stdio;

 	void main(string[] argv)
 	{
 	    auto a = [1, 2, 3];
 	    a.put(4);

 	    writefln("%s", a);
 	}

 One could expect the call to put() to append 4 to the array so the array  
 content would be [1, 2, 3, 4].
 Instead of this, I get "[2, 3]" to be printed. So I guess put() is  
 translated to

 	r.front = e; r.popFront();

 as written in std.range.put documentation.

 Is it the expected behaviour or is it a bug ?

Expected.  If you want an appendable array as an output range, use  
std.array.Appender.

auto a = appender([1,2,3]);
a.put(4);
writefln("%s", a.data);

-Steve

"Lars T. Kyllingstad" <public kyllingen.NOSPAMnet> writes:

On Fri, 12 Nov 2010 15:22:20 +0100, Olivier Pisano wrote:

 Hi,
 
 I am starting to play with output ranges and have trouble understanding
 how they do work on arrays. Consider the following code :
 
 	import std.array;
 	import std.range;
 	import std.stdio;
 
 	void main(string[] argv)
 	{
 	    auto a = [1, 2, 3];
 	    a.put(4);
 
 	    writefln("%s", a);
 	}
 
 One could expect the call to put() to append 4 to the array so the array
 content would be [1, 2, 3, 4].
 Instead of this, I get "[2, 3]" to be printed. So I guess put() is
 translated to
 
 	r.front = e; r.popFront();
 
 as written in std.range.put documentation.
 
 Is it the expected behaviour or is it a bug ?


Here's a discussion from earlier this year:

http://www.digitalmars.com/d/archives/digitalmars/D/
std.array.put_doesn_t_put_106871.html

-Lars

Olivier Pisano <olivier.pisano laposte.net> writes:

Le 12/11/2010 15:40, Lars T. Kyllingstad a écrit :
 Here's a discussion from earlier this year:

 http://www.digitalmars.com/d/archives/digitalmars/D/
 std.array.put_doesn_t_put_106871.html

 -Lars

Thanks to you and Steven.

I now understand why such a "weird" behavior.

Cheers,

Olivier