• =?UTF-8?B?THXDrXM=?= Marques (7/7) Jan 27 2016 This works:
• =?UTF-8?Q?Ali_=c3=87ehreli?= (14/20) Jan 27 2016 All I can say is the following compiles. I hope it works too. :)

=?UTF-8?B?THXDrXM=?= Marques <luis luismarques.eu> writes:

This works:

     int[][] a;
     RandomAccessFinite!(int[]) r = inputRangeObject(a);

What would be a good way to achieve something equivalent to this?:

     int[][] a;
     RandomAccessFinite!(RandomAccessFinite!int) r = 
inputRangeObject(a);

=?UTF-8?Q?Ali_=c3=87ehreli?= <acehreli yahoo.com> writes:

On 01/27/2016 08:59 PM, Luís Marques wrote:
 This works:

      int[][] a;
      RandomAccessFinite!(int[]) r = inputRangeObject(a);

 What would be a good way to achieve something equivalent to this?:

      int[][] a;
      RandomAccessFinite!(RandomAccessFinite!int) r = inputRangeObject(a);

All I can say is the following compiles. I hope it works too. :)

import std.range;
import std.algorithm;
import std.conv;

void main() {
     int[][] a;
     RandomAccessFinite!(RandomAccessFinite!int) r
         = inputRangeObject(
             a.map!(e => inputRangeObject(e).to!(RandomAccessFinite!int)));
}

Instead of to!(RandomAccessFinite!int) one can use the cast operator as 
well.

Ali