• nrgyzer (4/4) Feb 12 2010 Hello everyone,
• Justin Whear (2/5) Feb 12 2010 Well, integers don't have anything following the decimal, so there's not...
• BCS (33/44) Feb 12 2010 char[] AddCharEvery(char[] str, char c, int i)
• nrgyzer (2/58) Feb 13 2010 Thanks... that's exactly what I need :)

nrgyzer <nrgyzer gmail.com> writes:

Hello everyone,

I'm trying to split an integer into a integer with decimal points (or char[]
with decimal points). I already know that I can do this with
std.format.doFormat() but I don't know how I can use this to convert my int
(for example... 10000) to 10,000.

I hope anyone can help me :)

In this case... thanks so much for help

Justin Whear <justin economicmodeling.com> writes:

nrgyzer Wrote:

 Hello everyone,
 
 I'm trying to split an integer into a integer with decimal points (or char[]
with decimal points). I already know that I can do this with
std.format.doFormat() but I don't know how I can use this to convert my int
(for example... 10000) to 10,000.

Well, integers don't have anything following the decimal, so there's nothing to
do really. Unless you want to convert the integer to a string and append ".00"
or something. Perhaps you want to convert the integer to a string and insert
thousands separators? If so, you'll want to loop from the end of the string
towards the beginning, inserting a comma every 3 characters.

BCS <none anon.com> writes:

Hello Nrgyzer,

 Hello everyone,
 
 I'm trying to split an integer into a integer with decimal points (or
 char[] with decimal points). I already know that I can do this with
 std.format.doFormat() but I don't know how I can use this to convert
 my int (for example... 10000) to 10,000.
 
 I hope anyone can help me :)
 
 In this case... thanks so much for help
 

char[] AddCharEvery(char[] str, char c, int i)
{
    if(str.length > i) return AddCharEvery(str[0..$-i],c,i) ~ c ~ str[0..$-i];
    else return str;
}

or


char[] AddCharEvery(char[] str, char c, int i)
{
   if(str.length <= i) return str;

   auto ret = new char[str.length + (str.length-1)/i];

   int at = ret.length;
   while(str.length  > i)
   {
       ret[at-i..at] = str[$-i..$];
       ret[at-i-1] = c;
       at -= (i+1);
       str = str[0..$-i];
   }
   ret[0..at] = str;
   return ret;
}

//example
import std.stdio;
void main()
{
 writef("%s\n", AddCharEvery("100000000000000", ',', 3));
 writef("%s\n", AddCharEvery("10000000000000", ',', 3));
 writef("%s\n", AddCharEvery("1000000000000", ',', 3));
 writef("%s\n", AddCharEvery("100000000000", ',', 3));
}


--
<IXOYE><

nrgyzer <nrgyzer gmail.com> writes:

BCS Wrote:

 Hello Nrgyzer,
 
 Hello everyone,
 
 I'm trying to split an integer into a integer with decimal points (or
 char[] with decimal points). I already know that I can do this with
 std.format.doFormat() but I don't know how I can use this to convert
 my int (for example... 10000) to 10,000.
 
 I hope anyone can help me :)
 
 In this case... thanks so much for help
 

 
 char[] AddCharEvery(char[] str, char c, int i)
 {
     if(str.length > i) return AddCharEvery(str[0..$-i],c,i) ~ c ~ str[0..$-i];
     else return str;
 }
 
 or
 
 
 char[] AddCharEvery(char[] str, char c, int i)
 {
    if(str.length <= i) return str;
 
    auto ret = new char[str.length + (str.length-1)/i];
 
    int at = ret.length;
    while(str.length  > i)
    {
        ret[at-i..at] = str[$-i..$];
        ret[at-i-1] = c;
        at -= (i+1);
        str = str[0..$-i];
    }
    ret[0..at] = str;
    return ret;
 }
 
 //example
 import std.stdio;
 void main()
 {
  writef("%s\n", AddCharEvery("100000000000000", ',', 3));
  writef("%s\n", AddCharEvery("10000000000000", ',', 3));
  writef("%s\n", AddCharEvery("1000000000000", ',', 3));
  writef("%s\n", AddCharEvery("100000000000", ',', 3));
 }
 
 
 --
 <IXOYE><
 
 

Thanks... that's exactly what I need :)