• Joe Gottman (14/14) Sep 04 2006 Suppose I have a function f that has a lazy parameter x, and I pass it i...
• Walter Bright (3/6) Sep 04 2006 No, it isn't evaluated. The evaluation of it is wrapped up into another
• Joe Gottman (5/11) Sep 04 2006 OK. So what's the best way to force evaluation? Would just mentioning ...
• =?ISO-8859-1?Q?Jari-Matti_M=E4kel=E4?= (6/17) Sep 04 2006 Because g also uses lazy evaluation you have to evaluate x in f before
• Walter Bright (2/4) Sep 04 2006 Yes.
• Unknown W. Brackets (7/14) Sep 04 2006 Is it necessary to wrap it in another delegate?

"Joe Gottman" <jgottman carolina.rr.com> writes:

Suppose I have a function f that has a lazy parameter x, and I pass it into 
another function g that has a lazy parameter.  Will x be evaluated when it 
is passed to g?  For instance:

void g(lazy int x) {/* Do nothing */}

void f (lazy int x) {
    g(x);  //Is x evaluated here?
}

void main()
{
   int x = 0;
   f(++x);
    printf("%d\n", x); //Do we print 0 or 1?
}

Joe Gottman 

Walter Bright <newshound digitalmars.com> writes:

Joe Gottman wrote:
 Suppose I have a function f that has a lazy parameter x, and I pass it into 
 another function g that has a lazy parameter.  Will x be evaluated when it 
 is passed to g?

No, it isn't evaluated. The evaluation of it is wrapped up into another 
delegate and passed to g.

"Joe Gottman" <jgottman carolina.rr.com> writes:

"Walter Bright" <newshound digitalmars.com> wrote in message 
news:edi8s6$olu$1 digitaldaemon.com...
 Joe Gottman wrote:
 Suppose I have a function f that has a lazy parameter x, and I pass it 
 into another function g that has a lazy parameter.  Will x be evaluated 
 when it is passed to g?

 No, it isn't evaluated. The evaluation of it is wrapped up into another 
 delegate and passed to g.

OK.  So what's the best way to force evaluation?  Would just mentioning it 
in a line by itself work?

Joe Gottman 

=?ISO-8859-1?Q?Jari-Matti_M=E4kel=E4?= <jmjmak utu.fi.invalid> writes:

Joe Gottman wrote:
 "Walter Bright" <newshound digitalmars.com> wrote in message 
 news:edi8s6$olu$1 digitaldaemon.com...
 Joe Gottman wrote:
 Suppose I have a function f that has a lazy parameter x, and I pass it 
 into another function g that has a lazy parameter.  Will x be evaluated 
 when it is passed to g?

 No, it isn't evaluated. The evaluation of it is wrapped up into another 
 delegate and passed to g.

 
 OK.  So what's the best way to force evaluation?  Would just mentioning it 
 in a line by itself work?

Because g also uses lazy evaluation you have to evaluate x in f before
giving it forward as an argument to g. Still, the evaluated value gets
wrapped up into a delegate before it's finally usable in g as a simple
value.

The best way might be not to use lazy evaluation if it's not necessary.

Walter Bright <newshound digitalmars.com> writes:

Joe Gottman wrote:
 OK.  So what's the best way to force evaluation?  Would just mentioning it 
 in a line by itself work?

Yes.

"Unknown W. Brackets" <unknown simplemachines.org> writes:

Is it necessary to wrap it in another delegate?

Assuming it already has a delegate which returns int, it seems a 
possible optimization to simply pass this existing delegate on, without 
packaging it further...

Is that not the case, or simply a field for future optimization?

Thanks,
-[Unknown]


 Joe Gottman wrote:
 Suppose I have a function f that has a lazy parameter x, and I pass it 
 into another function g that has a lazy parameter.  Will x be 
 evaluated when it is passed to g?

 
 No, it isn't evaluated. The evaluation of it is wrapped up into another 
 delegate and passed to g.