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digitalmars.D - Help with stdarg templates

reply "Ted Williams" <ted.wil.no.spam verizon.net> writes:
Hi

I am using the stdarg templates as in the following code:

=====
int WriteLine( char[] format, ... )
{
    va_list args;

    alias va_start!(char []) start;
    alias va_arg!(Object) arg;

    start( args, format );
.
.
.
=====

When I compile this I get the following errors (with line numbers adjusted:)

console.d(8): function va_start (va_list ap,char[]parmn) does not match
argume nt types (ubyte*,char[])
console.d(8): cannot implicitly convert ubyte* to va_list

I've tried everything I can think of and can't find any combination of
things that will compile.  I think I have a fundamental flaw in my
understanding of the way templates work.  Can anyone help shed some light on
this for me?

Thanks,
Ted
Jun 01 2004
next sibling parent reply J C Calvarese <jcc7 cox.net> writes:
Ted Williams wrote:

 Hi
 
 I am using the stdarg templates as in the following code:
 
 =====
 int WriteLine( char[] format, ... )
 {
     va_list args;
 
     alias va_start!(char []) start;
     alias va_arg!(Object) arg;
 
     start( args, format );


This at least compiles:

import std.c.stdarg;
int WriteLine( char[] format, ... )
{
     va_list args;
     va_start!(char []) (args, format);
     va_end(args);
     return 1;
}
void main() {}

Here's a fuller example is available from 
http://www.dsource.org/tutorials/index.php?show_example=94
----------------------------------------------------------

import std.c.stdarg;

int foo(char *x, ...)
{
     va_list ap;

     va_start!(typeof(x))(ap, x);
     printf("&x = %p, ap = %p\n", &x, ap);

     int i;
     i = va_arg!(typeof(i))(ap);
     printf("i = %d\n", i);

     long l;
     l = va_arg!(typeof(l))(ap);
     printf("l = %lld\n", l);

     uint k;
     k = va_arg!(typeof(k))(ap);
     printf("k = %u\n", k);

     va_end(ap);

     return i + l + k;
}

void main()
{
     int j;

     j = foo("hello", 3, 23L, 4);
     printf("j = %d\n", j);
     assert(j == 30);
}


Hope that helps.


 ..
 ..
 ..
 =====
 
 When I compile this I get the following errors (with line numbers adjusted:)
 
 console.d(8): function va_start (va_list ap,char[]parmn) does not match
 argume nt types (ubyte*,char[])
 console.d(8): cannot implicitly convert ubyte* to va_list
 
 I've tried everything I can think of and can't find any combination of
 things that will compile.  I think I have a fundamental flaw in my
 understanding of the way templates work.  Can anyone help shed some light on
 this for me?
 
 Thanks,
 Ted


-- 
Justin (a/k/a jcc7)
http://jcc_7.tripod.com/d/
Jun 01 2004
parent "Ted Williams" <ted.wil.no.spam verizon.net> writes:
"J C Calvarese" <jcc7 cox.net> wrote in message
news:c9jn35$gu9$1 digitaldaemon.com...

 Ted Williams wrote:

 Hi

 I am using the stdarg templates as in the following code:

 =====
 int WriteLine( char[] format, ... )
 {
     va_list args;

     alias va_start!(char []) start;
     alias va_arg!(Object) arg;

     start( args, format );


 This at least compiles:

 import std.c.stdarg;
 int WriteLine( char[] format, ... )
 {
      va_list args;
      va_start!(char []) (args, format);
      va_end(args);
      return 1;
 }
 void main() {}

 Here's a fuller example is available from
 http://www.dsource.org/tutorials/index.php?show_example=94
 ----------------------------------------------------------

 import std.c.stdarg;

 int foo(char *x, ...)
 {
      va_list ap;

      va_start!(typeof(x))(ap, x);
      printf("&x = %p, ap = %p\n", &x, ap);

      int i;
      i = va_arg!(typeof(i))(ap);
      printf("i = %d\n", i);

      long l;
      l = va_arg!(typeof(l))(ap);
      printf("l = %lld\n", l);

      uint k;
      k = va_arg!(typeof(k))(ap);
      printf("k = %u\n", k);

      va_end(ap);

      return i + l + k;
 }


<snip>

I made my code look like the code above, and it still gives the same
compiler error as before:

console.d(101): function va_start (va_list ap,char[]parmn) does not match
argument types (ubyte*,char[])
console.d(101): cannot implicitly convert ubyte* to va_list

Could it be a compiler bug?
Jun 01 2004
prev sibling parent J Anderson <REMOVEanderson badmama.com.au> writes:
Ted Williams wrote:


Hi

I am using the stdarg templates as in the following code:

=====
int WriteLine( char[] format, ... )
{
    va_list args;

    alias va_start!(char []) start;
    alias va_arg!(Object) arg;

    start( args, format );
.
.
.
=====

When I compile this I get the following errors (with line numbers adjusted:)

console.d(8): function va_start (va_list ap,char[]parmn) does not match
argume nt types (ubyte*,char[])
console.d(8): cannot implicitly convert ubyte* to va_list

I've tried everything I can think of and can't find any combination of
things that will compile.  I think I have a fundamental flaw in my
understanding of the way templates work.  Can anyone help shed some light on
this for me?

Thanks,
Ted

  



import std.c.stdarg;

int WriteLine( char[] format, ... )
{
    va_list args;

    alias va_start!(char []) start;
    alias va_arg!(Object) arg;

    start( args, format );

    return 0;
}

void main(char[][] args)
{
    WriteLine("test");
}

Works for me in dmd (.91), so I can't see anything wrong with your code.

-- 
-Anderson: http://badmama.com.au/~anderson/
Jun 05 2004