• Genki Takiuchi (33/33) May 21 2004 I have tried to deduct arguments of template member function.

Genki Takiuchi <takiuchi khaki.plala.or.jp> writes:

I have tried to deduct arguments of template member function.
The result is as follows:


import std.c.stdio;

class Foo
{
    //! interface
    template func(alias arg1)
    {
        int func() { return funcImpl!(typeof(arg1))(arg1); }
    }
    //! implementation
    template funcImpl(T1)
    {
        int funcImpl(T1 value)
        {
            printf("%.*s\n", value.toString());
            return 0;
        }
    }
}

class Bar { char[] toString() { return "I am Bar!"; } }
class Baz { char[] toString() { return "I am Baz!"; } }

Bar bar;
Baz baz;

void main(char[][] arg)
{
    Foo foo = new Foo;

    bar = new Bar;
    foo.func!(bar)();

    baz = new Baz;
    foo.func!(baz)();
}


However, deductable arguments are limited to things able to be alias.