• nix (38/38) Nov 12 2004 Hallo,
• larrycowan (4/42) Nov 12 2004 Instead of matrix[0].length = 3;
• nix (10/59) Nov 12 2004 Thank you for the hint.
• Burton Radons (27/30) Nov 12 2004 Optionally, this will require fewer allocations:
• Buchan (8/35) Nov 13 2004 Whats wrong with int[3][3] matrix? Then at least the compiler knows

nix <nix_member pathlink.com> writes:

Hallo,  
 
i try to built a rectangular matrix. 
 
1 0 0      1 0 0 0   
0 1 0
or  0 1 0 0 or 5 times and so on 
0 0 1      0 0 1 0 
           0 0 0 1
int main() { 
        int[][] matrix; 
 
        matrix.length=3;
matrix[0].length=3; 
        for (int i=0; i < 3; i++){ 
                for
(int j=0; j < 3; j++){ 
                        if (i == j) {
matrix[j][i] = 1; 
                        } else {
matrix[j][i] = 0; 
                        } 
 
                } 
        }
return 0; 
} 
 
I get the following error message: 
Error: ArrayBoundsError
darr.d(11) 
 
This is line 11: matrix[j][i] = 0; 
 
 
  
 
  

larrycowan <larrycowan_member pathlink.com> writes:

Instead of matrix[0].length = 3;
Use matrix[i].length = 3;
and put it between the 2 for loops.

In article <cn2bk2$7c8$1 digitaldaemon.com>, nix says...
Hallo,  
 
i try to built a rectangular matrix. 
 
1 0 0      1 0 0 0   
0 1 0
or  0 1 0 0 or 5 times and so on 
0 0 1      0 0 1 0 
           0 0 0 1
int main() { 
        int[][] matrix; 
 
        matrix.length=3;
matrix[0].length=3; 
        for (int i=0; i < 3; i++){ 
                for
(int j=0; j < 3; j++){ 
                        if (i == j) {
matrix[j][i] = 1; 
                        } else {
matrix[j][i] = 0; 
                        } 
 
                } 
        }
return 0; 
} 
 
I get the following error message: 
Error: ArrayBoundsError
darr.d(11) 
 
This is line 11: matrix[j][i] = 0; 
 
 
  
 
  

nix <nix_member pathlink.com> writes:

Thank you for the hint. 
 
In article <cn2f3d$cm5$1 digitaldaemon.com>,
larrycowan says... 
 
Instead of matrix[0].length = 3; 
Use matrix[i].length

= 3; 
and put it between the 2 for loops. 
 
In article

<cn2bk2$7c8$1 digitaldaemon.com>, nix says... 
 
Hallo,   
  
i try to


built a rectangular matrix.  
  
1 0 0      1 0 0 0    
0 1 0 
or  0 1 0


0 or 5 times and so on  
0 0 1      0 0 1 0  
           0 0 0 1 
int


main() {  
        int[][] matrix;  
  
        matrix.length=3;
matrix[0].length=3;  
        for (int i=0; i < 3; i++){  
                for 
(int j=0; j < 3; j++){  
                        if (i == j) { 
matrix[j][i] = 1;  
                        } else { 
matrix[j][i] = 0;  
                        }  
  
                }  
        } 
return 0;  
}  
  
I get the following error message:  
Error: ArrayBoundsError 
darr.d(11)  
  
This is line 11: matrix[j][i] = 0;  
  
  
   
  
   
 
 

 
 

 

Burton Radons <burton-radons smocky.com> writes:

larrycowan wrote:
 Instead of matrix[0].length = 3;
 Use matrix[i].length = 3;
 and put it between the 2 for loops.

Optionally, this will require fewer allocations:

     template Matrix (Type)
     {
         Type [] [] allocate (size_t a, size_t b, Type [] array)
         {
             Type [] [] result;

             if (a && b)
                 assert (size_t.max / a >= b);
             assert (array.length >= a * b);
             result = new Type [] [a];

             size_t index = 0;
             foreach (inout Type [] item; result)
             {
                 item = array [index .. index + b];
                 index += b;
             }

             return result;
         }

         Type [] [] allocate (size_t a, size_t b)
         {
             return allocate (a, b, new Type [a * b]);
         }
     }

     float [] [] matrix = Matrix! (float).allocate (16, 16);

There should also be efficient resize and right/down-shifting (inserting 
space into the left or top of the matrix) functions; give me a second.

Buchan <kbuchan xtra.co.nz> writes:

On Fri, 12 Nov 2004 12:51:14 +0000 (UTC), nix <nix_member pathlink.com>  
wrote:

 Hallo,
 i try to built a rectangular matrix.
 1 0 0      1 0 0 0
 0 1 0
 or  0 1 0 0 or 5 times and so on
 0 0 1      0 0 1 0
            0 0 0 1
 int main() {
         int[][] matrix;
        matrix.length=3;
 matrix[0].length=3;
         for (int i=0; i < 3; i++){
                 for
 (int j=0; j < 3; j++){
                         if (i == j) {
 matrix[j][i] = 1;
                         } else {
 matrix[j][i] = 0;
                         }
                }
         }
 return 0;
 }
 I get the following error message:
 Error: ArrayBoundsError
 darr.d(11)
 This is line 11: matrix[j][i] = 0;

Whats wrong with int[3][3] matrix? Then at least the compiler knows
how big it is... unless you want to figure out how big they are at RT.
(Its also faster and in one block of memory, meaning you can do more  
tricks)

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