• Lynn Allan (20/20) Sep 25 2004
• Ben Hinkle (10/34) Sep 25 2004 icky. The std.string module's atoi(char[] s) just calls

"Lynn Allan" <l_d_allan adelphia.net> writes:

<alert comment="newbie">

I was wondering why the compiler rejected lines 6 and 7. The documentation
doesn't mention anything about:
intC atoi(char*)

#import std.string;
#void main ()










// .\Test.d(6): function atoi overloads intC (char*) and long(char[]s) both
match argument list for atoi
// .\Test.d(7): function atoi overloads intC (char*) and long(char[]s) both
match argument list for atoi

</alert>

Ben Hinkle <bhinkle4 juno.com> writes:

Lynn Allan wrote:

 <alert comment="newbie">
 
 I was wondering why the compiler rejected lines 6 and 7. The documentation
 doesn't mention anything about:
 intC atoi(char*)
 
 #import std.string;
 #void main ()





 




 // .\Test.d(6): function atoi overloads intC (char*) and long(char[]s)
 both match argument list for atoi
 // .\Test.d(7): function atoi overloads intC (char*) and long(char[]s)
 both match argument list for atoi
 
 </alert>

icky. The std.string module's atoi(char[] s) just calls
atoi(toStringz(numStr1)) so probably the simplest thing to do is call
long num1 = atoi(toStringz(numStr1));
(don't worry about the toStringz allocating a new string because the literal
"1234" has a trailing 0) or as you suggest just go ahead and tell the
compiler which atoi by casting. It is unfortunate that the D atoi overloads
the C atoi. Maybe all those C functions should be private and add some
std.c.string or something.

-Ben