c++.rtl - cpow()
- Wes (18/18) Jan 17 2006 Also, cpow() does not seem to be working properly. The imaginary part o...
- Walter Bright (1/1) Jan 22 2006 Thanks, I'll investigate.
Also, cpow() does not seem to be working properly. The imaginary part of the result is always zero. For example: -------------------------- #include <complex.h> #include <stdio.h> main() { double complex z1, z2, z3; z1 = 0.1 + 0.2*I; z2 = 0.3 + 0.4*I; z3 = cpow(z1, z2); printf("%f, %f\n", creal(z3), cimag(z3) ); return 0; } -------------------------- The output should be 0.395227, -0.108108 but is instead: 0.395227, 0.000000 -Wes Loewer
Jan 17 2006