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c++.dos.32-bits - Unable to use void.

reply greppinFunk <greppinFunk_member pathlink.com> writes:
Hi, I'm new to C and am learning it for my software engineering course. I'm
trying to compile a basic array program;

#include <stdio.h>
main()
{
int a[10];
for(int i=0;i<10;i++)
{
a[i]=i;
}
printarr(a);
}

void printarr(int a[])
{
for(int i=0;i<10;i++)
{
printf("value in array %d\n",a[i]);
}
}

When I compile I get the output;

C:\dm\bin>dmc third.c
{
^
third.c(13) : Error: 'printarr' previously declared as something else
It was declared as: int C func(int *)
It is now declared: void C func(int *)
--- errorlevel 1

It works when I change void to int, however I thought that without a return
value void was used. The code is taken from C & Data Structures by P.S Deshpande
and O.G Kakde.

Thanks.
Oct 14 2005
parent Jan Knepper <jan smartsoft.us> writes:
greppinFunk wrote:

 Hi, I'm new to C and am learning it for my software engineering course. I'm
 trying to compile a basic array program;
 
 #include <stdio.h>


void printarr(int a[]);		// PROTOTYPE


 main()
 {
 int a[10];
 for(int i=0;i<10;i++)
 {
 a[i]=i;
 }
 printarr(a);
 }
 
 void printarr(int a[])
 {
 for(int i=0;i<10;i++)
 {
 printf("value in array %d\n",a[i]);
 }
 }
 
 When I compile I get the output;
 
 C:\dm\bin>dmc third.c
 {
 ^
 third.c(13) : Error: 'printarr' previously declared as something else
 It was declared as: int C func(int *)
 It is now declared: void C func(int *)
 --- errorlevel 1
 
 It works when I change void to int, however I thought that without a return
 value void was used. The code is taken from C & Data Structures by P.S
Deshpande
 and O.G Kakde.
 
 Thanks.
 
 



-- 
ManiaC++
Jan Knepper

But as for me and my household, we shall use Mozilla...
www.mozilla.org
Oct 14 2005