• noobi (12/12) Aug 01 2003 hello,
• Walter (4/16) Aug 01 2003 Because achar is statically initialized to NULL - your program never set...
• noobi (4/25) Aug 02 2003 I need to put the Ascii character of code variable in a buffer (achar)
• Walter (7/37) Aug 02 2003 it
• Gisle Vanem (10/16) Aug 01 2003 I'm amased this doesn't crash (assuming it's a 32-bit program).
• Walter (3/16) Aug 02 2003 No, it doesn't. Sorry.
• raju (15/15) Oct 31 2008 Hello,

noobi <noobi_member pathlink.com> writes:

hello,

#include <stdio.h>

char *achar;
int code;

main()
{
code = 65;
sprintf(achar, "%c", code);
printf("char1=%c \n",code);  // output > char1=A
printf("char2=%s",achar);    // output > char2=(null)

}

Why char2=(null) and not A ?

"Walter" <walter digitalmars.com> writes:

"noobi" <noobi_member pathlink.com> wrote in message
news:bgdrgp$f8i$1 digitaldaemon.com...
 hello,

 #include <stdio.h>

 char *achar;
 int code;

 main()
 {
 code = 65;
 sprintf(achar, "%c", code);
 printf("char1=%c \n",code);  // output > char1=A
 printf("char2=%s",achar);    // output > char2=(null)

 }

 Why char2=(null) and not A ?

Because achar is statically initialized to NULL - your program never sets it
to point to a buffer.

noobi <noobi_member pathlink.com> writes:

In article <bge9fl$svp$1 digitaldaemon.com>, Walter says...
"noobi" <noobi_member pathlink.com> wrote in message
news:bgdrgp$f8i$1 digitaldaemon.com...
 hello,

 #include <stdio.h>

 char *achar;
 int code;

 main()
 {
 code = 65;
 sprintf(achar, "%c", code);
 printf("char1=%c \n",code);  // output > char1=A
 printf("char2=%s",achar);    // output > char2=(null)

 }

 Why char2=(null) and not A ?

Because achar is statically initialized to NULL - your program never sets it
to point to a buffer.


I need to put the Ascii character of code variable in a buffer (achar)
and display it with printf() later
How can i do it ?

"Walter" <walter digitalmars.com> writes:

"noobi" <noobi_member pathlink.com> wrote in message
news:bgfpf7$2bh6$1 digitaldaemon.com...
 In article <bge9fl$svp$1 digitaldaemon.com>, Walter says...
"noobi" <noobi_member pathlink.com> wrote in message
news:bgdrgp$f8i$1 digitaldaemon.com...
 hello,

 #include <stdio.h>

 char *achar;
 int code;

 main()
 {
 code = 65;
 sprintf(achar, "%c", code);
 printf("char1=%c \n",code);  // output > char1=A
 printf("char2=%s",achar);    // output > char2=(null)

 }

 Why char2=(null) and not A ?

Because achar is statically initialized to NULL - your program never sets


it
to point to a buffer.


 I need to put the Ascii character of code variable in a buffer (achar)
 and display it with printf() later
 How can i do it ?

Write:

    char achar[2];

    achar[0] = code;
    achar[1] = 0;

"Gisle Vanem" <giva users.sourceforge.net> writes:

"noobi" <noobi_member pathlink.com> wrote:

 char *achar;
 int code;

 main()
 {
 code = 65;
 sprintf(achar, "%c", code);

I'm amased this doesn't crash (assuming it's a 32-bit program).
If it's is a 16-bit program, it shouldn't crash, but give a
"NULL pointer assignment" message at program exit. Ref.
Borland's c0.asm. Walter, does DMC have a similar __checknull()
function?

-- 
Gisle V.


/bin/laden: Not found

"Walter" <walter digitalmars.com> writes:

"Gisle Vanem" <giva users.sourceforge.net> wrote in message
news:bgeb83$urj$1 digitaldaemon.com...
 "noobi" <noobi_member pathlink.com> wrote:

 char *achar;
 int code;

 main()
 {
 code = 65;
 sprintf(achar, "%c", code);

 I'm amased this doesn't crash (assuming it's a 32-bit program).
 If it's is a 16-bit program, it shouldn't crash, but give a
 "NULL pointer assignment" message at program exit. Ref.
 Borland's c0.asm. Walter, does DMC have a similar __checknull()
 function?

No, it doesn't. Sorry.

raju <raju_member pathlink.com> writes:

Hello,
I don't know which compiler you have used, however mostly standard
compilers will compile the code, but when you try to run the
object file, you can see a "Illegal address reference" kind of
error, that will abend your running process.

Here you have used a variable achar, which is "char *".
As we know that if you want to store any data in a pointer
variable we need to allocate memory for the data.
Here before allocating the memory, you are using the pointer
variable to store that "code" data.
So here sprintf should traps this out and abend the process.

As you have got the output and it is (null), this is might be,
because of the compiler.

Hope this helps.
:-)