• Tydr Schnubbis (6/6) Apr 18 2004 Apart from the obvious difference in their intended usage, are they
• C. Sauls (9/16) Apr 18 2004 The 'inout' attribute essentially means pass-by-reference, 'in' is just
• Tydr Schnubbis (9/16) Apr 18 2004 Sorry, I meant to ask about the difference between out and inout, not in
• =?ISO-8859-1?Q?Sigbj=F8rn_Lund_Olsen?= (6/23) Apr 24 2004 'out' will set the variable to its .init value. So if you pass a float

Tydr Schnubbis <nobody nowhere.fake> writes:

Apart from the obvious difference in their intended usage, are they
different?  Does inout guarantee that a variable has been assigned to
prior to being used as an argument?  Do both inout and out guarantee
that they parameters will be assigned to inside the function? I think


Tor

"C. Sauls" <ibisbasenji yahoo.com> writes:

The 'inout' attribute essentially means pass-by-reference, 'in' is just 
there for completeness and means to use whatever the default is 
(pass-by-value for pretty much everything, pass-by-reference for 
classes).  And no they don't gurantee assignment, but since all D 
variables have a default value (.init) one could argue that they are 
technically guranteed to have something anyhow.

-C. Sauls
-Invironz

Tydr Schnubbis wrote:
 Apart from the obvious difference in their intended usage, are they
 different?  Does inout guarantee that a variable has been assigned to
 prior to being used as an argument?  Do both inout and out guarantee
 that they parameters will be assigned to inside the function? I think

 
 Tor

Tydr Schnubbis <nobody nowhere.fake> writes:

Tydr Schnubbis wrote:
 Apart from the obvious difference in their intended usage, are they
 different?  Does inout guarantee that a variable has been assigned to
 prior to being used as an argument?  Do both inout and out guarantee
 that they parameters will be assigned to inside the function? I think

 
 Tor

Sorry, I meant to ask about the difference between out and inout, not in
and inout.  But I guess any guarantee that an inout parameter, if a
variable, has been assigned to before used as an argument, would apply
to in as well.  I realize that being forced to assign to a variable
to avoid compiler errors or warnings might be annoying if you are happy
with the default value.  But to have this kind of enforcement could also
be very useful.

Tor

=?ISO-8859-1?Q?Sigbj=F8rn_Lund_Olsen?= <sigbjorn lundolsen.net> writes:

Tydr Schnubbis wrote:
 Tydr Schnubbis wrote:
 
 Apart from the obvious difference in their intended usage, are they
 different?  Does inout guarantee that a variable has been assigned to
 prior to being used as an argument?  Do both inout and out guarantee
 that they parameters will be assigned to inside the function? I think


 Tor

 
 Sorry, I meant to ask about the difference between out and inout, not in
 and inout.  But I guess any guarantee that an inout parameter, if a
 variable, has been assigned to before used as an argument, would apply
 to in as well.  I realize that being forced to assign to a variable
 to avoid compiler errors or warnings might be annoying if you are happy
 with the default value.  But to have this kind of enforcement could also
 be very useful.

'out' will set the variable to its .init value. So if you pass a float 
with 0.75 as an out, it will be set to NaN as it is passed to the 
function. inout doesn't do this, the value of 0.75 is left alone.

Cheers,
Sigbjørn Lund Olsen