D - std.string.split
- Scott Egan (10/10) Apr 14 2004 May I suggest that a third split function be offered. In VB(.net) there...
- Ant (6/16) Apr 14 2004 It's usefull.
- Scott Egan (5/27) Apr 14 2004 Good so how do I help?
- Ant (14/17) Apr 14 2004 I don't know.
- Scott Egan (44/44) Apr 15 2004 import std.c.stdio;
May I suggest that a third split function be offered. In VB(.net) there is the option to split and limit the number of returned parts, eg: dim str as string = "QAZ = Test Log value = 5" dim parts as string() parts = str.split("=", 2) This results in parts(0) = "QAZ " and parts(1) = " Test Log value = 5" I find this incredibly useful in log file and other text manipulation work. So the D equivalent should be: char[][] split(char[] s, char[] delim, int parts) Thoughts?
Apr 14 2004
In article <c5jf7p$1hfv$1 digitaldaemon.com>, Scott Egan says...May I suggest that a third split function be offered. In VB(.net) there is the option to split and limit the number of returned parts, eg: dim str as string = "QAZ = Test Log value = 5" dim parts as string() parts = str.split("=", 2) This results in parts(0) = "QAZ " and parts(1) = " Test Log value = 5" I find this incredibly useful in log file and other text manipulation work. So the D equivalent should be: char[][] split(char[] s, char[] delim, int parts) Thoughts?It's usefull. I needed it. I use it (just rejoin after split). let's got for it. Ant
Apr 14 2004
Good so how do I help? "Ant" <Ant_member pathlink.com> wrote in message news:c5k2g6$2ea0$1 digitaldaemon.com...In article <c5jf7p$1hfv$1 digitaldaemon.com>, Scott Egan says...isMay I suggest that a third split function be offered. In VB(.net) therework.the option to split and limit the number of returned parts, eg: dim str as string = "QAZ = Test Log value = 5" dim parts as string() parts = str.split("=", 2) This results in parts(0) = "QAZ " and parts(1) = " Test Log value = 5" I find this incredibly useful in log file and other text manipulationSo the D equivalent should be: char[][] split(char[] s, char[] delim, int parts) Thoughts?It's usefull. I needed it. I use it (just rejoin after split). let's got for it. Ant
Apr 14 2004
On Thu, 15 Apr 2004 08:10:22 +1000, Scott Egan wrote:Good so how do I help?I don't know. meanwhile you can use this crude implementation: char[][] split (char[] string, char[] delim, int parts) { char[][] tks = std.string.split(string, delim); if ( parts>0 && tks.length>parts ) { tks[parts-1] = std.string.join(tks[parts-1..tks.length],delim); tks.length = parts; } return tks; } Ant
Apr 14 2004
import std.c.stdio; import std.string; /************************************** * Split s[] into an array of words, * using delim[] as the delimiter. * Stop when the number of parts have * been found. */ char[][] split(char[] s, char[] delim, int parts) in { assert(delim.length > 0); assert(parts >= 0); } body { uint count = 0; uint last = 0; uint current; char[][] words; // If the deliminator won't fit in the string then just return the string. if(s.length < delim.length) { words = new char[][1]; words[0] = s; return words; } // init the returned array - lucky we know max size; words = new char[][parts]; // is words.length = parts justas good? // chars to check and parts to get for(current = 0; (current <= s.length - delim.length) && (count < parts - 1); current++) { if(s[current..current + delim.length] == delim) { // printf("%i, %i, %i \n", last, current, count); words[count] = s[last..current]; // .dup ???? current += delim.length; // step over deliminator last = current; count++; } } words[count] = s[last..s.length]; // remainder of string words.length = count + 1; // trim the returned arry to correct length - if all ready correct does this do anything ??? return words; }
Apr 15 2004