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D - help with std.zip

reply Ant <duitoolkit yahoo.ca> writes:
How to add new members to an existing ZipArchive?
I just read the file,
create the ZipArchive instance from the file
add the new member
build the archive
and write it back to a file

All the previous members became 0 length
(can be listed but unzip does not create any files)

Am I missing something?

any idea? thanks.

Ant
Mar 15 2004
next sibling parent "Matthew" <matthew stlsoft.org> writes:
I was just trying to use it myself, but because I'm in a rush I've resorted
to using Ruby.

Anyone have a couple of simple std.zlib samples they would like to post?


"Ant" <duitoolkit yahoo.ca> wrote in message
news:pan.2004.03.16.03.12.06.886848 yahoo.ca...

 How to add new members to an existing ZipArchive?
 I just read the file,
 create the ZipArchive instance from the file
 add the new member
 build the archive
 and write it back to a file

 All the previous members became 0 length
 (can be listed but unzip does not create any files)

 Am I missing something?

 any idea? thanks.

 Ant
Mar 16 2004
prev sibling parent reply =?ISO-8859-1?Q?Julio_Jim=E9nez?= <jujibo inicia.es> writes:
Ant wrote:

 How to add new members to an existing ZipArchive?
 I just read the file,
 create the ZipArchive instance from the file
 add the new member
 build the archive
 and write it back to a file
 
 All the previous members became 0 length
 (can be listed but unzip does not create any files)
 
 Am I missing something?
 
 any idea? thanks.
 
 Ant
 


I think you can't in that way.

You must create a ZipArchive object with the zip file you want to open...
then can get the ArchiveMember from directory member, defined:
  (ArchiveMember[char[]] directory;)
Create a New ZipArchive object and add this ArchiveMember plus the files 
you want... then delete de old zip file and rename the new one created

But I think there is something wrong in std.zip module


regards


Julio
Mar 16 2004
parent reply =?ISO-8859-1?Q?Julio_Jim=E9nez?= <jujibo inicia.es> writes:
Julio Jiménez wrote:

 Ant wrote:
 



 I think you can't in that way.
 
 You must create a ZipArchive object with the zip file you want to open...
 then can get the ArchiveMember from directory member, defined:
  (ArchiveMember[char[]] directory;)
 Create a New ZipArchive object and add this ArchiveMember plus the files 
 you want... then delete de old zip file and rename the new one created
 
 But I think there is something wrong in std.zip module
 
 
 regards
 
 
 Julio
 


Sorry... yes... you can

a little example:
// Program for testing zlib
// Modified to append a file to a existing zipfile...


import std.file;
import std.date;
import std.zip;
import std.zlib;

int main(char[][] args)
{
     byte[] buffer;
     std.zip.ZipArchive zr;
     char[] zipname;
     ubyte[] data;

     testzlib();
     if (args.length > 1)
  zipname = args[1];
     else
  zipname = "test.zip";
     buffer = cast(byte[])std.file.read(zipname);
     zr = new std.zip.ZipArchive(cast(void[])buffer);
     printf("comment = '%.*s'\n", zr.comment);
     //zr.print();

     foreach (ArchiveMember de; zr.directory)
     {

       printf("date = '%.*s'\n", 
std.date.toString(std.date.toDtime(de.time)));
       //data = zr.expand(de);

     }

     printf("**Success**\n");

     ArchiveMember am = new ArchiveMember();
     am.compressionMethod = 8;
     am.name = "foo2.bar"; // name for your new archive to append
     am.time = toDosFileTime(getUTCtime());
     //am.extra = cast(ubyte[])"ExTrA";
     am.expandedData = cast(ubyte[])"We all live in a yellow submarine, 
a yellow submarine";
     am.expandedSize = am.expandedData.length;
     zr.addMember(am);
     void[] data2 = zr.build(); // build  new zip file
     std.file.write(zipname, cast(byte[])data2); // overwrite the old 
file with new data

     return 0;
}

void arrayPrint(ubyte[] array)
{
     //printf("array %p,%d\n", (void*)array, array.length);
     for (int i = 0; i < array.length; i++)
     {
  printf("%02x ", array[i]);
  if (((i + 1) & 15) == 0)
      printf("\n");
     }
     printf("\n\n");
}

void testzlib()
{
     ubyte[] src = cast(ubyte[])
"the quick brown fox jumps over the lazy dog\r
the quick brown fox jumps over the lazy dog\r
";
     ubyte[] dst;

     arrayPrint(src);
     dst = cast(ubyte[])std.zlib.compress(cast(void[])src);
     arrayPrint(dst);
     src = cast(ubyte[])std.zlib.uncompress(cast(void[])dst);
     arrayPrint(src);
}


but it create a corrupted zip file.... try to test it, its a begining... 
:-) i only had 5 minutes to test...

later


Julio
Mar 16 2004
parent Ant <duitoolkit yahoo.ca> writes:
On Tue, 16 Mar 2004 11:52:30 +0100, Julio Jiménez wrote:


 Julio Jiménez wrote:

 Ant wrote:
 


 

 I think you can't in that way.
 
 You must create a ZipArchive object with the zip file you want to open...
 then can get the ArchiveMember from directory member, defined:
  (ArchiveMember[char[]] directory;)
 Create a New ZipArchive object and add this ArchiveMember plus the files 
 you want... then delete de old zip file and rename the new one created
 
 But I think there is something wrong in std.zip module




I think you're right.

Anyone has experience witht the zip module?

Ant
Mar 16 2004