• Owen (3/3) Feb 20 2004 If I have an array of 32 bits, can I cast this to an integer? Or do I n...
• J Anderson (28/32) Feb 21 2004 You'll have to use a union (although I would argue for a cast version).
• Ben Hinkle (15/15) Feb 21 2004 "Owen" wrote in message
• J Anderson (4/20) Feb 21 2004 I stand corrected.

Owen <Owen_member pathlink.com> writes:

If I have an array of 32 bits, can I cast this to an integer?  Or do I need to
declare a union of this array 
with an integer an then access the array as an integer through that?

J Anderson <REMOVEanderson badmama.com.au> writes:

Owen wrote:

If I have an array of 32 bits, can I cast this to an integer?  Or do I need to
declare a union of this array 
with an integer an then access the array as an integer through that?

  

You'll have to use a union (although I would argue for a cast version). 
It's pretty doggie code (well at least my version is).

union bittoarray
{
    bit [] BIT;
    int [] INT;
}

int [] convert(bit [] array)
{
    bittoarray cov;
    cov.BIT = array;
    cov.INT.length = cov.INT.length / (int.sizeof * 8);
    return cov.INT; //Note that you should no longer use the bit version
}


int main ( char [] [] args )
{
    bit [] barray;
   
    barray.length = 32;
    barray[2] = 1;   
   
    int [] iarray = convert(barray);

    printf("%d\n",  iarray.length);
    printf("%d\n",  iarray[0]);
}

-- 
-Anderson: http://badmama.com.au/~anderson/

"Ben Hinkle" <bhinkle4 juno.com> writes:

"Owen" <Owen_member pathlink.com> wrote in message
news:c16l96$25bg$1 digitaldaemon.com...
| If I have an array of 32 bits, can I cast this to an integer?  Or do I need to
| declare a union of this array
| with an integer an then access the array as an integer through that?

How about
   bit[] p1;
   int[] p2;
   p1 = new bit[32];
   p1[0] = 1;
   p1[2] = 1;
   p2 = (cast(int*)p1)[0..1];
   printf("%d\n",p2[0]);
   p2[0] = 4;
   printf("%d %d\n",p1[0],p1[2]);

J Anderson <REMOVEanderson badmama.com.au> writes:

Ben Hinkle wrote:

"Owen" <Owen_member pathlink.com> wrote in message
news:c16l96$25bg$1 digitaldaemon.com...
| If I have an array of 32 bits, can I cast this to an integer?  Or do I need to
| declare a union of this array
| with an integer an then access the array as an integer through that?

How about
   bit[] p1;
   int[] p2;
   p1 = new bit[32];
   p1[0] = 1;
   p1[2] = 1;
   p2 = (cast(int*)p1)[0..1];
   printf("%d\n",p2[0]);
   p2[0] = 4;
   printf("%d %d\n",p1[0],p1[2]);
  

I stand corrected.

-- 
-Anderson: http://badmama.com.au/~anderson/