• Lars Ivar Igesund (8/8) Feb 09 2004 The following code crash dmd with no error message:
• Lars Ivar Igesund (10/23) Feb 09 2004 Another one in a similar vein. The following code crash
• Sam McCall (4/16) Feb 09 2004 But isn't foo a variable not a type?
• Lars Ivar Igesund (3/21) Feb 10 2004 You're right of course. My fault. But it shouldn't segfault.
• Andy Friesen (9/20) Feb 09 2004 the expression 'int function() foo;' doesn't declare a type. It creates...
• Lars Ivar Igesund (3/31) Feb 10 2004 You're right of course. My fault. But it shouldn't segfault anyway.

Lars Ivar Igesund <larsivar igesund.net> writes:

The following code crash dmd with no error message:

<--------------------

int function() foo;
typedef foo bar;

<--------------------

I suppose it isn't allowed to typedef function pointers,
but still, an error message would be nice :)

Lars Ivar Igesund

Lars Ivar Igesund <larsivar igesund.net> writes:

Another one in a similar vein. The following code crash
dmd with no error message:

<----------------------

int function() foo;
int bar(foo fp);

<----------------------

I believe that function pointers as function parameters
are allowed.

Lars Ivar Igesund


Lars Ivar Igesund wrote:

 The following code crash dmd with no error message:
 
 <--------------------
 
 int function() foo;
 typedef foo bar;
 
 <--------------------
 
 I suppose it isn't allowed to typedef function pointers,
 but still, an error message would be nice :)
 
 Lars Ivar Igesund

Sam McCall <tunah.d tunah.net> writes:

Lars Ivar Igesund wrote:
 Another one in a similar vein. The following code crash
 dmd with no error message:
 
 <----------------------
 
 int function() foo;
 int bar(foo fp);
 
 <----------------------
 
 I believe that function pointers as function parameters
 are allowed.

But isn't foo a variable not a type?
Should error anyway.
Sam

Lars Ivar Igesund <larsivar igesund.net> writes:

Sam McCall wrote:

 Lars Ivar Igesund wrote:
 
 Another one in a similar vein. The following code crash
 dmd with no error message:

 <----------------------

 int function() foo;
 int bar(foo fp);

 <----------------------

 I believe that function pointers as function parameters
 are allowed.

 
 But isn't foo a variable not a type?
 Should error anyway.
 Sam


You're right of course. My fault. But it shouldn't segfault.

Lars Ivar Igesund

Andy Friesen <andy ikagames.com> writes:

Lars Ivar Igesund wrote:

 The following code crash dmd with no error message:
 
 <--------------------
 
 int function() foo;
 typedef foo bar;
 
 <--------------------
 
 I suppose it isn't allowed to typedef function pointers,
 but still, an error message would be nice :)

the expression 'int function() foo;' doesn't declare a type.  It creates 
a global called foo, which is a pointer to a function that accepts no 
arguments, and returns an int.

'typedef foo bar;' on the next line is therefore complete nonsense.

What you probably want is

     typedef int function() bar;

Regardless, it shouldn't segfault the compiler. :)

  -- andy

Lars Ivar Igesund <larsivar igesund.net> writes:

Andy Friesen wrote:

 Lars Ivar Igesund wrote:
 
 The following code crash dmd with no error message:

 <--------------------

 int function() foo;
 typedef foo bar;

 <--------------------

 I suppose it isn't allowed to typedef function pointers,
 but still, an error message would be nice :)

 
 
 the expression 'int function() foo;' doesn't declare a type.  It creates 
 a global called foo, which is a pointer to a function that accepts no 
 arguments, and returns an int.
 
 'typedef foo bar;' on the next line is therefore complete nonsense.
 
 What you probably want is
 
     typedef int function() bar;
 
 Regardless, it shouldn't segfault the compiler. :)
 
  -- andy

You're right of course. My fault. But it shouldn't segfault anyway.

Lars Ivar Igesund