D - operator overloading
- Ivan Senji (27/27) Jan 25 2004 1. i like D very much1
1. i like D very much1
2. I only recently got some time to start exploring it and i have a
question:
i have this code:
class Cout
{
Cout opShl(char[] x)
{
printf("%.*s",x);
return this;
}
Cout opShl(int x)
{
printf("%d",x);
return this;
}
...
}
The idea is to make a class cout that would act like c++ cout.
Is there any way to write something like:
Cout opShl(Cout c,A f)
{
//printf that prints object f of type A
return c;
}
it doesn't work the way i would like it, i have to explicitly call the
function ti print type A!
Jan 25 2004
opShl_r will make you happy!
"Ivan Senji" <ivan.senji public.srce.hr> wrote in message
news:bv163k$ckg$1 digitaldaemon.com...
1. i like D very much1
2. I only recently got some time to start exploring it and i have a
question:
i have this code:
class Cout
{
Cout opShl(char[] x)
{
printf("%.*s",x);
return this;
}
Cout opShl(int x)
{
printf("%d",x);
return this;
}
...
}
The idea is to make a class cout that would act like c++ cout.
Is there any way to write something like:
Cout opShl(Cout c,A f)
{
//printf that prints object f of type A
return c;
}
it doesn't work the way i would like it, i have to explicitly call the
function ti print type A!
Jan 25 2004
what if you have a toString() function in A
and then call
printf( f.toString());
Phill.
"Ivan Senji" <ivan.senji public.srce.hr> wrote in message
news:bv163k$ckg$1 digitaldaemon.com...
1. i like D very much1
2. I only recently got some time to start exploring it and i have a
question:
i have this code:
class Cout
{
Cout opShl(char[] x)
{
printf("%.*s",x);
return this;
}
Cout opShl(int x)
{
printf("%d",x);
return this;
}
...
}
The idea is to make a class cout that would act like c++ cout.
Is there any way to write something like:
Cout opShl(Cout c,A f)
{
//printf that prints object f of type A
return c;
}
it doesn't work the way i would like it, i have to explicitly call the
function ti print type A!
Jan 25 2004









"Robert" <no spam.ne.jp> 