D - operator overloading
- Ivan Senji (27/27) Jan 25 2004 1. i like D very much1
1. i like D very much1 2. I only recently got some time to start exploring it and i have a question: i have this code: class Cout { Cout opShl(char[] x) { printf("%.*s",x); return this; } Cout opShl(int x) { printf("%d",x); return this; } ... } The idea is to make a class cout that would act like c++ cout. Is there any way to write something like: Cout opShl(Cout c,A f) { //printf that prints object f of type A return c; } it doesn't work the way i would like it, i have to explicitly call the function ti print type A!
Jan 25 2004
opShl_r will make you happy! "Ivan Senji" <ivan.senji public.srce.hr> wrote in message news:bv163k$ckg$1 digitaldaemon.com...1. i like D very much1 2. I only recently got some time to start exploring it and i have a question: i have this code: class Cout { Cout opShl(char[] x) { printf("%.*s",x); return this; } Cout opShl(int x) { printf("%d",x); return this; } ... } The idea is to make a class cout that would act like c++ cout. Is there any way to write something like: Cout opShl(Cout c,A f) { //printf that prints object f of type A return c; } it doesn't work the way i would like it, i have to explicitly call the function ti print type A!
Jan 25 2004
what if you have a toString() function in A and then call printf( f.toString()); Phill. "Ivan Senji" <ivan.senji public.srce.hr> wrote in message news:bv163k$ckg$1 digitaldaemon.com...1. i like D very much1 2. I only recently got some time to start exploring it and i have a question: i have this code: class Cout { Cout opShl(char[] x) { printf("%.*s",x); return this; } Cout opShl(int x) { printf("%d",x); return this; } ... } The idea is to make a class cout that would act like c++ cout. Is there any way to write something like: Cout opShl(Cout c,A f) { //printf that prints object f of type A return c; } it doesn't work the way i would like it, i have to explicitly call the function ti print type A!
Jan 25 2004