D - A bug, feature or misunderstanding?
- Gennadi Pais (10/10) Aug 05 2003 Hi All,
- Matthew Wilson (3/13) Aug 05 2003 Use %.*s for the string format specifier
- Gennadi Pais (2/21) Aug 05 2003
- Matthew Wilson (5/30) Aug 05 2003 Sorry, I don't understand. In your example you said you done "%s", where...
- Gennadi Pais (13/46) Aug 05 2003 Please pay attention to the next cut from the D's spec (Arrays section):
- Matthew Wilson (17/67) Aug 05 2003 I may be missing something here - possible - but you seem to be
- Matthew Wilson (7/80) Aug 05 2003 Correction, the two examples I meant were
- Gennadi Pais (8/100) Aug 05 2003 Dear All,
- Paul Runde (12/28) Aug 05 2003 From html/d/arrays.html
- Mike Wynn (10/20) Aug 05 2003 ^^^ see this line
- Walter (1/1) Sep 12 2003 Thanks for pointing this out. I've corrected the spec.
Hi All,
during my first trying of the D language in the code:
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
I received compiler error:
.. undefined identifier append
Compiler is: Digital Mars D Compiler Beta v0.68
The tested code is from the D spec.
Thanks.
Aug 05 2003
Use %.*s for the string format specifier
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
Hi All,
during my first trying of the D language in the code:
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
I received compiler error:
.. undefined identifier append
Compiler is: Digital Mars D Compiler Beta v0.68
The tested code is from the D spec.
Thanks.
Aug 05 2003
That's the way I implemented it, but what about the spec? In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...Use %.*s for the string format specifier "Gennadi Pais" <Gennadi_member pathlink.com> wrote in message news:bgnqjm$nsb$1 digitaldaemon.com...Hi All, during my first trying of the D language in the code: char[] str = "blah-blah"; str.append(0); printf ("str is: %s\n", str); I received compiler error: .. undefined identifier append Compiler is: Digital Mars D Compiler Beta v0.68 The tested code is from the D spec. Thanks.
Aug 05 2003
Sorry, I don't understand. In your example you said you done "%s", whereas I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out of my jurisdiction, I'm afraid. ;) "Gennadi Pais" <Gennadi_member pathlink.com> wrote in message news:bgnte9$qg8$1 digitaldaemon.com...That's the way I implemented it, but what about the spec? In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...Use %.*s for the string format specifier "Gennadi Pais" <Gennadi_member pathlink.com> wrote in message news:bgnqjm$nsb$1 digitaldaemon.com...Hi All, during my first trying of the D language in the code: char[] str = "blah-blah"; str.append(0); printf ("str is: %s\n", str); I received compiler error: .. undefined identifier append Compiler is: Digital Mars D Compiler Beta v0.68 The tested code is from the D spec. Thanks.
Aug 05 2003
Please pay attention to the next cut from the D's spec (Arrays section):
______________________________
There are two ways to use printf() with D strings. The first is to add a
terminating 0, and cast the result to a char*:
str.append(0);
printf("the string is '%s'\n", (char *)str);
The second way is to use the precision specifier. The way D arrays are laid out,
the length comes first, so the following works:
printf("the string is '%.*s'\n", str);
______________________________
I just want to say that the first described above way is not compiled and failed
with an error (see my first message).
In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s", whereas
I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out of
my jurisdiction, I'm afraid. ;)
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
That's the way I implemented it, but what about the spec?
In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
Hi All,
during my first trying of the D language in the code:
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
I received compiler error:
.. undefined identifier append
Compiler is: Digital Mars D Compiler Beta v0.68
The tested code is from the D spec.
Thanks.
Aug 05 2003
I may be missing something here - possible - but you seem to be
contradicting yourself.
Your first example was
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
Now in this you do neither of
printf ("str is: %s\n", (char*)str);
or
printf ("str is: %.*s\n", (char*)str);
Surely this is clear?
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgoe7f$1b2c$1 digitaldaemon.com...
Please pay attention to the next cut from the D's spec (Arrays section):
______________________________
There are two ways to use printf() with D strings. The first is to add a
terminating 0, and cast the result to a char*:
str.append(0);
printf("the string is '%s'\n", (char *)str);
The second way is to use the precision specifier. The way D arrays are
laid out,
the length comes first, so the following works:
printf("the string is '%.*s'\n", str);
______________________________
I just want to say that the first described above way is not compiled and
failed
with an error (see my first message).
In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s",
whereas
I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out
of
my jurisdiction, I'm afraid. ;)
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
That's the way I implemented it, but what about the spec?
In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
Hi All,
during my first trying of the D language in the code:
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
I received compiler error:
.. undefined identifier append
Compiler is: Digital Mars D Compiler Beta v0.68
The tested code is from the D spec.
Thanks.
Aug 05 2003
Correction, the two examples I meant were
printf ("str is: %s\n", (char*)str);
or
printf ("str is: %.*s\n", str);
"Matthew Wilson" <matthew stlsoft.org> wrote in message
news:bgp97g$272e$1 digitaldaemon.com...
I may be missing something here - possible - but you seem to be
contradicting yourself.
Your first example was
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
Now in this you do neither of
printf ("str is: %s\n", (char*)str);
or
printf ("str is: %.*s\n", (char*)str);
Surely this is clear?
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgoe7f$1b2c$1 digitaldaemon.com...
Please pay attention to the next cut from the D's spec (Arrays section):
______________________________
There are two ways to use printf() with D strings. The first is to add a
terminating 0, and cast the result to a char*:
str.append(0);
printf("the string is '%s'\n", (char *)str);
The second way is to use the precision specifier. The way D arrays are
laid out,
the length comes first, so the following works:
printf("the string is '%.*s'\n", str);
______________________________
I just want to say that the first described above way is not compiled
and
failed
with an error (see my first message).
In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s",
whereas
I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out
of
my jurisdiction, I'm afraid. ;)
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
That's the way I implemented it, but what about the spec?
In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
Hi All,
during my first trying of the D language in the code:
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
I received compiler error:
.. undefined identifier append
Compiler is: Digital Mars D Compiler Beta v0.68
The tested code is from the D spec.
Thanks.
Aug 05 2003
Gennadi Pais <Gennadi_member pathlink.com>
Dear All,
thank for the explanation how can I print a string out, but if you will pay
attention I didn't ask about how to (I've found some different ways), but the
issue was the compilation error because of lack of the array's <append> method.
I think the clear and right spec is exactly what the new language need. So I
want to ask somebody who has permission to edit D's documentation to fix that
over there.
In article <bgpb2f$28tu$1 digitaldaemon.com>, Matthew Wilson says...
Correction, the two examples I meant were
printf ("str is: %s\n", (char*)str);
or
printf ("str is: %.*s\n", str);
"Matthew Wilson" <matthew stlsoft.org> wrote in message
news:bgp97g$272e$1 digitaldaemon.com...
I may be missing something here - possible - but you seem to be
contradicting yourself.
Your first example was
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
Now in this you do neither of
printf ("str is: %s\n", (char*)str);
or
printf ("str is: %.*s\n", (char*)str);
Surely this is clear?
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgoe7f$1b2c$1 digitaldaemon.com...
Please pay attention to the next cut from the D's spec (Arrays section):
______________________________
There are two ways to use printf() with D strings. The first is to add a
terminating 0, and cast the result to a char*:
str.append(0);
printf("the string is '%s'\n", (char *)str);
The second way is to use the precision specifier. The way D arrays are
laid out,
the length comes first, so the following works:
printf("the string is '%.*s'\n", str);
______________________________
I just want to say that the first described above way is not compiled
and
failed
with an error (see my first message).
In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s",
whereas
I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out
of
my jurisdiction, I'm afraid. ;)
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
That's the way I implemented it, but what about the spec?
In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
Hi All,
during my first trying of the D language in the code:
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
I received compiler error:
.. undefined identifier append
Compiler is: Digital Mars D Compiler Beta v0.68
The tested code is from the D spec.
Thanks.
Aug 05 2003
Gennadi Pais wrote:
Hi All,
during my first trying of the D language in the code:
char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);
I received compiler error:
.. undefined identifier append
Compiler is: Digital Mars D Compiler Beta v0.68
The tested code is from the D spec.
Thanks.
From html/d/arrays.html
" Since strings, however, are not 0 terminated in D, when transfering a
pointer to a string to C, add a terminating 0:
str.append(0); "
However, append is not listed as an array property. Try this:
import string;
char[] str = "blah-blah";
printf ("str is: %s\n", toStringz(str));
toStringz appends the terminator.
Paul
Aug 05 2003
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message news:bgnqjm$nsb$1 digitaldaemon.com...Hi All, during my first trying of the D language in the code: char[] str = "blah-blah"; str.append(0);^^^ see this lineprintf ("str is: %s\n", str); I received compiler error: .. undefined identifier append^^^ this error is because char[] does not have an append function.Compiler is: Digital Mars D Compiler Beta v0.68 The tested code is from the D spec. Thanks.try char[] str = "blah-blah"; printf ("str is: %.*s\n", str); "%.*s" is the D string format spec. if you want to append to a string use operator ~ str = str ~ "\0"; or str = str ~ \0; /// note no ' ' as you would in C.
Aug 05 2003
Thanks for pointing this out. I've corrected the spec.
Sep 12 2003