• Keir (10/10) Feb 18 2003 import c.stdio;
• Michael Slater (18/32) Feb 18 2003 There seems to be something amiss --
• Burton Radons (4/15) Feb 18 2003 It's not returning a nul-terminated string. Using:

"Keir" <keir verizon.net> writes:

import c.stdio;
import string;

int main(char[][] args)
  {
  printf(toString(0));
  return 0;
  }

I would expect to see a zero when I run this...
instead I see "0123456789"

is anybody else having issues with this?

Michael Slater <mail effectivity.com> writes:

Keir wrote:
 import c.stdio;
 import string;
 
 int main(char[][] args)
   {
   printf(toString(0));
   return 0;
   }
 
 I would expect to see a zero when I run this...
 instead I see "0123456789"
 
 is anybody else having issues with this?
 

There seems to be something amiss --

import c.stdio;
import string;

int main(char[][] args)
{
         int n = 5;
         puts(toString(n));
         puts(toString(0));
         puts(toString(n));
         printf("%s\n", "past puts");
         return 0;
}

56789
0123456789
56789
Error: Access Violation

--ms

Burton Radons <loth users.sourceforge.net> writes:

Keir wrote:
 import c.stdio;
 import string;
 
 int main(char[][] args)
   {
   printf(toString(0));
   return 0;
   }
 
 I would expect to see a zero when I run this...
 instead I see "0123456789"

It's not returning a nul-terminated string.  Using:

    printf (toStringz (toString (0)));

Should format it correctly.