• "Wichetael" <wichetael gmx.net> Mar 11 2004
• "Wichetael" <wichetael gmx.net> Mar 11 2004
• Heinz Saathoff <hsaat bre.ipnet.de> Mar 12 2004
• "Wichetael" <wichetael gmx.net> Mar 16 2004

Could anybody tell me what this error means exactly? I can't find it in the
documentation on the site.

Regards, Remko van der Vossen.

Ah, I found the error, apparently I left an empty set of parenthesis, where
there had been a variable initialization. But is it really false C++ to have
an empty set of parenthesis in a variable declaration?

Also, I still don't get what the error is trying to tell me, and why is it
not included in the on-line documentation?

Regards, Remko van der Vossen

"Wichetael" <wichetael gmx.net> wrote in message
news:c2q22g$2tnt$1 digitaldaemon.com...
 Could anybody tell me what this error means exactly? I can't find it in


 documentation on the site.

 Regards, Remko van der Vossen.

Hello,

Wichetael wrote...
 Ah, I found the error, apparently I left an empty set of parenthesis, where
 there had been a variable initialization. But is it really false C++ to have
 an empty set of parenthesis in a variable declaration?


if you have

  struct XYZ {
      XYZ() {}
      ~XYZ() {}
  };

and write a variable definition as

  XYZ variable();  // parenthesis here!
 
then the compiler will not interpret this as a variable definition but 
as a function declaration (variable is a function taking no arguments 
and returning a XYZ).
To define a variable the parenthesis must be taken away.


- Heinz

Of course, doh...

Thanks anyway,

Remko van der Vossen.

"Heinz Saathoff" <hsaat bre.ipnet.de> wrote in message
news:MPG.1abbc008a9fc1a5f9896da news.digitalmars.com...
 Hello,

 Wichetael wrote...
 Ah, I found the error, apparently I left an empty set of parenthesis,




 there had been a variable initialization. But is it really false C++ to




 an empty set of parenthesis in a variable declaration?


 if you have

   struct XYZ {
       XYZ() {}
       ~XYZ() {}
   };

 and write a variable definition as

   XYZ variable();  // parenthesis here!

 then the compiler will not interpret this as a variable definition but
 as a function declaration (variable is a function taking no arguments
 and returning a XYZ).
 To define a variable the parenthesis must be taken away.


 - Heinz