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c++ - powl

↑ ↓ ← "David Grimes" <dgrimes friberg.us> writes:
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main(){
printf("1^inf = %Lg\n", powl(1.0l, strtold("inf", 0)));
return 0;
}

The output of the above code compiled with DMC v8.36 is: 1^inf = nan
Do you have plans to conform the compiler to IEC 60599?

Thanks,
David
Oct 04 2003
↑ ↓ → "Gisle Vanem" <giva users.sourceforge.net> writes:
"David Grimes" <dgrimes friberg.us> wrote:

 int main(){
 printf("1^inf = %Lg\n", powl(1.0l, strtold("inf", 0)));
 return 0;
 }

 The output of the above code compiled with DMC v8.36 is: 1^inf = nan
 Do you have plans to conform the compiler to IEC 60599?

Can you pass args to powl() that fails __fdclassify* and expect meaningful results? Try: long double x = strtold("inf",0); if (isnormal(x)) printf("1^inf = %Lg\n", powl(1.0l, x)); else puts ("NaN"); --gv
Oct 04 2003