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c++ - powl bug
The following code produce wrong result: #include <math.h> #include <stdio.h> int main() { long double a = powl(-0.0397739, 310.954); long double b = -5.12198e11; printf("(%Lg)^(%Lg) = %Lg", a, b, powl(a, b)); return 0; } The used compiler is Digital Mars Compiler v8.29n. Apr 21 2003
In article <b81iu3$2smm$1 digitaldaemon.com>, Steve Hall (sthall lorrexinc.com) says...The following code produce wrong result: #include <math.h> #include <stdio.h> int main() { long double a = powl(-0.0397739, 310.954); long double b = -5.12198e11; printf("(%Lg)^(%Lg) = %Lg", a, b, powl(a, b)); return 0; } Apr 22 2003
I agree with you, but according to C99, the math and lcc-win32 v3.8 the result of the following code should be: (nan)^(3.5) = nan. #include <math.h> #include <stdio.h> int main() { long double a = powl(-1, 0.5); long double b = 3.5; printf("(%Lg)^(%Lg) = %Lg", a, b, powl(a, b)); return 0; } The result from dmc v8.29n is: (nan)^(3.5) = 3.36128e-4932. The software that I develop depend on precision C99 floating-point arithmetic. "Larry Brasfield" <larry_brasfield snotmail.com> wrote in message news:MPG.190ea07eab0c3d7e9896a4 news.digitalmars.com...In article <b81iu3$2smm$1 digitaldaemon.com>, Steve Hall (sthall lorrexinc.com) says...The following code produce wrong result: #include <math.h> #include <stdio.h> int main() { long double a = powl(-0.0397739, 310.954); long double b = -5.12198e11; printf("(%Lg)^(%Lg) = %Lg", a, b, powl(a, b)); return 0; } Apr 22 2003
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