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c++ - template conversion operator
template <class T>
struct A
{ };
template<class T>
struct B
{
B &operator=(const B &b)
{
return *this;
}
B &operator=(A<T> a)
{
return *this;
}
template<class U>
operator A<U>()
// Error: 'B<int >::operator A<int >' is already defined
{
return A<U>();
}
};
int main()
{
B<int> a;
a = B<int>();
return 0;
}
Extracted from STLport's std::auto_ptr - it's quite annoying as there is no
clean workaround...
bye, Christof
--
http://cmeerw.org JID: cmeerw jabber.at
mailto cmeerw at web.de
...and what have you contributed to the Net?
Dec 23 2002
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