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c++ - template conversion operator
template <class T> struct A { }; template<class T> struct B { B &operator=(const B &b) { return *this; } B &operator=(A<T> a) { return *this; } template<class U> operator A<U>() // Error: 'B<int >::operator A<int >' is already defined { return A<U>(); } }; int main() { B<int> a; a = B<int>(); return 0; } Extracted from STLport's std::auto_ptr - it's quite annoying as there is no clean workaround... bye, Christof -- http://cmeerw.org JID: cmeerw jabber.at mailto cmeerw at web.de ...and what have you contributed to the Net? Dec 23 2002
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