• pascal111 (14/14) Jul 24 2022 In the next code, we used "%s" format with receiving an integer
• Adam D Ruppe (11/15) Jul 24 2022 The D things in std.stdio, writef and readf, use %s to just mean
• pascal111 (2/14) Jul 24 2022 It's like an automatic figuring for the data type.

pascal111 <judas.the.messiah.111 gmail.com> writes:

In the next code, we used "%s" format with receiving an integer 
value, while from C experience, we know that we use "%d" or "%i" 
formats, so what "%s" stands for here, I guess it's for receiving 
string data type?

import std.stdio;

     void main() {
         write("How many students are there? ");

         /* The definition of the variable that will be used to
          * store the information that is read from the input. */
         int studentCount;

         // Storing the input data to that variable
         readf("%s", &studentCount);

         writeln("Got it: There are ", studentCount, " students.");
     }

Adam D Ruppe <destructionator gmail.com> writes:

On Sunday, 24 July 2022 at 23:12:46 UTC, pascal111 wrote:
 In the next code, we used "%s" format with receiving an integer 
 value, while from C experience, we know that we use "%d" or 
 "%i" formats, so what "%s" stands for here, I guess it's for 
 receiving string data type?

The D things in std.stdio, writef and readf, use %s to just mean 
default for the given type. Since you passed it an int, the 
function knows it got an int (this is different than C, where the 
function only knows the format string so it requires you to get 
it right) and just automatically picks a default representation 
to scan.

You can writef("%s %s", "foo", 5); and it will see "foo" is a 
string and thus do it as a regular %s then see 5 is an int and 
since it knows, and you asked for just the default as-string 
representation, it will convert just like %d would.

pascal111 <judas.the.messiah.111 gmail.com> writes:

On Sunday, 24 July 2022 at 23:48:59 UTC, Adam D Ruppe wrote:
 On Sunday, 24 July 2022 at 23:12:46 UTC, pascal111 wrote:
 [...]

 The D things in std.stdio, writef and readf, use %s to just 
 mean default for the given type. Since you passed it an int, 
 the function knows it got an int (this is different than C, 
 where the function only knows the format string so it requires 
 you to get it right) and just automatically picks a default 
 representation to scan.

 You can writef("%s %s", "foo", 5); and it will see "foo" is a 
 string and thus do it as a regular %s then see 5 is an int and 
 since it knows, and you asked for just the default as-string 
 representation, it will convert just like %d would.

It's like an automatic figuring for the data type.